Java 导出为 XML 不起作用

发布于 2024-12-21 05:23:26 字数 2891 浏览 0 评论 0原文

我一直在使用教程将我的对象导出为 XML...我看到以下对象出现以下错误。我不确定出了什么问题......首先我收到了有关注释掉的 id 和 name 元素的错误,然后是有关根元素的错误。

    Mapped exception to response: 500 (Internal Server Error) javax.ws.rs.WebApplicationException: 
   com.sun.xml.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions java.sql.Date does not have a no-arg default constructor.
this problem is related to the following location: at java.sql.Date at private java.sql.Date contentmanagement.Guest.signingDate at contentmanagement.Guest at com.sun.jersey.core.provider.jaxb.AbstractRootElementProvider.writeTo(AbstractRootElementProvider.java:159) at com.sun.jersey.spi.container.ContainerResponse.write(ContainerResponse.java:306) at.....

这似乎是我的约会对象,我们将不胜感激您的反馈!

package contentmanagement;

import java.io.Serializable;
import java.sql.Date;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@Entity
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Guest implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    private String name;
    private Date signingDate;

    public Guest() {
    }

    public Guest(String name) {
        this.name = name;
        this.signingDate = new Date(System.currentTimeMillis());
    }

    //@XmlElement(name = "id")
    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    //@XmlElement(name = "name")
    public String getName() {
        return name;
    }

    @Override
    public int hashCode() {
        int hash = 0;
        hash += (id != null ? id.hashCode() : 0);
        return hash;
    }

    @Override
    public boolean equals(Object object) {
        // TODO: Warning - this method won't work in the case the id fields are not set
        if (!(object instanceof Guest)) {
            return false;
        }
        Guest other = (Guest) object;
        if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return name + " (signed on " + signingDate + ")";
    }

}

旁注:有没有更好的方式查看日志?比在显示堆栈跟踪的实心字符串中?有什么特别的应用程序或者什么吗?目前我正在查看我的日志: http://localhost:4848/common/index.jsf

抛出错误的控制器是:

@GET @Path("getGuestsXml")
@Produces("application/xml")
public Guest getGuestsXml() {
    Guest response = new Guest();

    //response.setId(9L);

    return response;
}

I've been using a tutorial to get my object exported as XML... I'm seeing the below error with the below object. I'm not sure what's going wrong.... first I got errors about the id and name elements that are commented out, then an error about the root element.

    Mapped exception to response: 500 (Internal Server Error) javax.ws.rs.WebApplicationException: 
   com.sun.xml.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions java.sql.Date does not have a no-arg default constructor.
this problem is related to the following location: at java.sql.Date at private java.sql.Date contentmanagement.Guest.signingDate at contentmanagement.Guest at com.sun.jersey.core.provider.jaxb.AbstractRootElementProvider.writeTo(AbstractRootElementProvider.java:159) at com.sun.jersey.spi.container.ContainerResponse.write(ContainerResponse.java:306) at.....

IT seems like my date Your feedback would be appreciated!

package contentmanagement;

import java.io.Serializable;
import java.sql.Date;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@Entity
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Guest implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;
    private String name;
    private Date signingDate;

    public Guest() {
    }

    public Guest(String name) {
        this.name = name;
        this.signingDate = new Date(System.currentTimeMillis());
    }

    //@XmlElement(name = "id")
    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    //@XmlElement(name = "name")
    public String getName() {
        return name;
    }

    @Override
    public int hashCode() {
        int hash = 0;
        hash += (id != null ? id.hashCode() : 0);
        return hash;
    }

    @Override
    public boolean equals(Object object) {
        // TODO: Warning - this method won't work in the case the id fields are not set
        if (!(object instanceof Guest)) {
            return false;
        }
        Guest other = (Guest) object;
        if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return name + " (signed on " + signingDate + ")";
    }

}

Side note: is there any better way to view logs? than in a solid string showing a stack trace? Any special apps or anything? Currently I'm viewing my logs at: http://localhost:4848/common/index.jsf

The controller throwing the error is:

@GET @Path("getGuestsXml")
@Produces("application/xml")
public Guest getGuestsXml() {
    Guest response = new Guest();

    //response.setId(9L);

    return response;
}

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流星番茄 2024-12-28 05:23:26

看起来 java.sql.Date 是麻烦制造者,因为它没有零参数构造函数。您可能需要为其编写串行器/适配器。

在这里找到更多信息,希望它有帮助:

jaxb unmarshal timestamp

如何将 java.sql.Date 序列化为很长,当使用 Web 服务时?

就日志/堆栈跟踪而言:您还喜欢什么其他视图?从开发人员的角度来看,详细的堆栈跟踪很好。对于系统的用户,您永远不想显示它们,因此请确保捕获这些内容并显示一个温和的错误页面。

Looks like java.sql.Date is the trouble maker as it does not have a zero-arg constructor. You may have to program a serializer/adapter for it.

Find more here, hoping it helps:

jaxb unmarshal timestamp

How to serialize java.sql.Date as Long, when using web services?

As far as logs/stacktraces are concerned: What other view would you prefer? Seen from a developer's perspective, verbose stacktraces are nice. For users of your system, you never want to show them, so make sure you catch these and show a gentle error page instead.

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