我可以仅自动装配构造函数注入的多个参数之一吗？

发布于 2024-12-21 05:15:46 字数 944 浏览 3 评论 0原文

我有一个 bean，我想向其中注入一组资源。

org.springframework.core.io.Resource[]

实际上，InputStreamSource 数组就足够了。我希望我的 bean 定义看起来像：

<bean id="..." class="com.usta.SomeClass">
    <constructor-arg value="classpath:somedir/*.xml"/>
</bean>

我的构造函数在哪里：

public SomeClass(InputStreamSource[] sources);

因为那行不通，我不情愿地选择了

public SomeClass(InputStreamSource[] sources, ResourcePatternResolver resolver);

但现在我如何注入 ApplicationContext （这是一个 ResourcePatternResolver ）通过构造函数注入到这个bean中？或者我可以说只自动连接这个构造函数参数吗？

我知道 Setter 注入（使用 ResourceLoaderAware）可以解决这个问题，但我尽可能坚持使用构造函数注入。

SomeClass 使用 Resources 预先进行一些初始化；使用setter注入，我将不得不推迟初始化，并且无法声明一些SomeClass的字段final。

原文

I have a bean, into which I wanted to inject an array of Resources.

org.springframework.core.io.Resource[]

Actually, an array of InputStreamSource was good enough. I wanted my bean definition to look something like:

<bean id="..." class="com.usta.SomeClass">
    <constructor-arg value="classpath:somedir/*.xml"/>
</bean>

where my constructor was:

public SomeClass(InputStreamSource[] sources);

Since that wouldn't work, I reluctantly chose to have

public SomeClass(InputStreamSource[] sources, ResourcePatternResolver resolver);

But now how can I inject the ApplicationContext (which is a ResourcePatternResolver) into this bean via constructor injection? Or can I say only auto-wire this constructor argument?

I know Setter Injection (with ResourceLoaderAware) would solve this but I am sticking to Consructor Injections as far as possible.

SomeClass uses the Resources some initialization up front; with setter injection I will have to defer initialization and not be able to declare a number of SomeClass's fields final.

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山人契 2024-12-28 05:15:46

这应该适合你......

构造函数：

public SomeClass(final Resource[] resources) { ... }

配置：

<bean id="patternResolver" class="org.springframework.core.io.support.PathMatchingResourcePatternResolver" />

<bean id="..." class="com.usta.SomeClass">
    <constructor-arg value="#{patternResolver.getResources('somedir/*.xml')}" />
</bean>

This should work for you ...

Constructor:

public SomeClass(final Resource[] resources) { ... }

Configuration:

<bean id="patternResolver" class="org.springframework.core.io.support.PathMatchingResourcePatternResolver" />

<bean id="..." class="com.usta.SomeClass">
    <constructor-arg value="#{patternResolver.getResources('somedir/*.xml')}" />
</bean>

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