读取 xml 并在控制器中查找？

发布于 2024-12-20 16:03:29 字数 1205 浏览 3 评论 0原文

我有一个示例 xml，

<Lookup> 
    <Controller Name="Activity1" >
       <action Name="Editactivity1" appgroup="Something" productcode="SomethingElse"/>    
    </Controller> 
    <Controller Name="Activity2">    
       <action Name="Editactivity2" appgroup="Something1" productcode="SomethingElse2"/>  
    </Controller>
</Lookup>

控制器名称和操作名称存储在变量中。

var cntName;
var actName;

根据这些值，我必须查找此 Xml 并获取相应的 appgroup 和 productcode 值。

注意：cntName 的示例值为 Activity1 或 Activity2 或 ActivityN。
actName 的示例值为 EditActivity1 或 EditActivity2 或 EditActivityN。

因此，根据这些值，我必须查找 xml，希望我清楚我的问题陈述。

我正在使用传统的 xmldatadocument 读取 xml，如何将其更改为 LINQ？示例如下。

XmlDocument xmlDocAppMod = new XmlDocument();
strFileName = System.Configuration.ConfigurationManager.AppSettings["AppModOptListPath"].ToString();
strFileLocation = System.Web.HttpContext.Current.Server.MapPath("~/" + strFileName);

xmlDocAppMod.Load(strFileLocation);

谢谢，阿达什

原文

I have a sample xml

<Lookup> 
    <Controller Name="Activity1" >
       <action Name="Editactivity1" appgroup="Something" productcode="SomethingElse"/>    
    </Controller> 
    <Controller Name="Activity2">    
       <action Name="Editactivity2" appgroup="Something1" productcode="SomethingElse2"/>  
    </Controller>
</Lookup>

I have the controller name and action name stored in variables.

var cntName;
var actName;

Based on these values I have to look up this Xml and fetch the corresponding appgroup and productcode values.

Note: example values for cntName would be Activity1 or Activity2 or ActivityN.
Example values for actName would be EditActivity1 or EditActivity2 or EditActivityN.

So based on these values i have to look up the xml, Hope I am clear with my problem statement.

I am reading my xml using traditional xmldatadocument, how do i change it to LINQ? Sample below.

XmlDocument xmlDocAppMod = new XmlDocument();
strFileName = System.Configuration.ConfigurationManager.AppSettings["AppModOptListPath"].ToString();
strFileLocation = System.Web.HttpContext.Current.Server.MapPath("~/" + strFileName);

xmlDocAppMod.Load(strFileLocation);

Thanks,
Adarsh

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谁对谁错谁最难过 2024-12-27 16:03:30

基本上，您有多种选择：

从磁盘加载文档并创建 xPath 表达式来评估它：

var doc = new XmlDocument();
doc.Load(文件名);
var 节点 = doc.SelectSingleNode(
    string.Format("/Lookup/Controller[@Name='{0}']/action[@Name='{1}']", cntName, actName));

if (节点!= null)
{

        var appGroup = node.Attributes["appgroup"].Value;
        var 产品代码 = node.Attributes["产品代码"].Value;
}

另一个选项可能是使用 XDocument：

 var doc = XDocument.Load("");
    var action = doc.Descendants("Controller")
        .Where(c =>;
                   {
                       var controllerName = c.Attribute("名称");
                       返回控制器名称！= null &&控制器名称.值.等于(cntName);
                   })
        .FirstOrDefault()
        .Elements("动作")
        .Where(a =>;
                   {
                       var controllerName = a.Attribute("名称");
                       返回控制器名称！= null &&控制器名称.值.等于(actName);
                   })
        .FirstOrDefault();
    var appGroup = action.Attribute("appgroup").Value;
    var 产品代码 = action.Attribute("产品代码").Value;

更新：

当然，您也可以将 xPath 与 Linq-to-XML 结合使用：

var doc = XDocument.Load("");
var action = (XElement) doc.XPathEvaluate(string.Format("/Lookup/Controller[@Name='{0}']/action[@Name='{1}']", cntName, actName));
var appGroup = action.Attribute("appgroup").Value;
var productCode = action.Attribute("productcode").Value;

Basically, you have several options:

Load the document from disk and create an xPath expression to evaluate it:

var doc = new XmlDocument();
doc.Load(fileName);
var node = doc.SelectSingleNode(
    string.Format("/Lookup/Controller[@Name='{0}']/action[@Name='{1}']", cntName, actName));

if (node != null)
{

        var appGroup = node.Attributes["appgroup"].Value;
        var productcode = node.Attributes["productcode"].Value;
}

Another option could be to use XDocument:

    var doc = XDocument.Load("");
    var action = doc.Descendants("Controller")
        .Where(c =>
                   {
                       var controllerName = c.Attribute("Name");
                       return controllerName != null && controllerName.Value.Equals(cntName);
                   })
        .FirstOrDefault()
        .Elements("action")
        .Where(a =>
                   {
                       var controllerName = a.Attribute("Name");
                       return controllerName != null && controllerName.Value.Equals(actName);
                   })
        .FirstOrDefault();
    var appGroup = action.Attribute("appgroup").Value;
    var productCode = action.Attribute("productcode").Value;

UPDATE:

Of course, you could use xPath with Linq-to-XML as well:

var doc = XDocument.Load("");
var action = (XElement) doc.XPathEvaluate(string.Format("/Lookup/Controller[@Name='{0}']/action[@Name='{1}']", cntName, actName));
var appGroup = action.Attribute("appgroup").Value;
var productCode = action.Attribute("productcode").Value;

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