如何将参数传递给 django 通用视图

发布于 2024-12-20 11:02:28 字数 769 浏览 0 评论 0原文

我想将一个数字传递到我的通用视图（DetailView）以获取一个对象这是我的代码

Urlpattern

(r'^newreportview/(?P<number>\w+)/$', NewReportView.as_view()),

View Class

class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    context_object_name = "newreportview"
    def get_queryset(self):
        task= get_object_or_404(MyTask,applicationnnumber=self.args[0])
        return task

我猜这行错误消息中有问题

name = get_object_or_404(MyTask,applicationnnumber=self.args[0])

：

Exception Type: IndexError
Exception Value:
tuple index out of range

How should I pass 'number' to this generic view and get a Mytask 对象带有这个“数字”？

谢谢

原文

I would like to pass a number to my generic view (DetailView) to get one object Here is my code

Urlpattern

(r'^newreportview/(?P<number>\w+)/
View Class
class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    context_object_name = "newreportview"
    def get_queryset(self):
        task= get_object_or_404(MyTask,applicationnnumber=self.args[0])
        return task

I guess something is wrong  in this line
name = get_object_or_404(MyTask,applicationnnumber=self.args[0])

error message:
Exception Type: IndexError
Exception Value:
tuple index out of range

How should I pass 'number' to this generic view and get a Mytask object with this 'number'?
Thanks
, NewReportView.as_view()),

View Class

I guess something is wrong in this line

error message:

How should I pass 'number' to this generic view and get a Mytask object with this 'number'?

Thanks

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老娘不死你永远是小三 2024-12-27 11:02:28

你已经错过了一般观点的全部要点。对于简单的 DetailView - 这是单个对象的视图 - 您只需在类中定义 model 和 slug 属性：（

(r'^newreportview/(\d+)/
您也可以轻松地传递这些属性三个作为 URL 定义中的参数，因此根本不需要创建子类。）
您没有获得 self.args 值的原因是您将参数作为 kwarg 传递，而不是一个参数。因此，self.kwargs['number'] 会起作用，就像我在此处显示的修改后的 URL 一样。
, NewReportView.as_view()),  

class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    model = MyTask
    slug = 'applicationnnumber'

您也可以轻松地传递这些属性三个作为 URL 定义中的参数，因此根本不需要创建子类。）

您没有获得 self.args 值的原因是您将参数作为 kwarg 传递，而不是一个参数。因此，self.kwargs['number'] 会起作用，就像我在此处显示的修改后的 URL 一样。

You have missed the entire point of generic views. For a simple DetailView - which is a view of a single object - you just define the model and slug attributes in the class:

(r'^newreportview/(\d+)/
(You could also just as easily have passed those three as parameters in the URL definition, so no need to make a subclass at all.)
The reason why you were getting no values for self.args is that you had passed your parameter as a kwarg, not an arg. So self.kwargs['number'] would have worked, as would the revised URL I've shown here.
, NewReportView.as_view()),  

class NewReportView(DetailView):
    template_name = "report/newreportview.html"
    model = MyTask
    slug = 'applicationnnumber'

(You could also just as easily have passed those three as parameters in the URL definition, so no need to make a subclass at all.)

The reason why you were getting no values for self.args is that you had passed your parameter as a kwarg, not an arg. So self.kwargs['number'] would have worked, as would the revised URL I've shown here.

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