NSMutableDictionary 未获得预期输出。

Question

它只为 NSMutableDictionary 输出一组，而不是两者。我想使用 NSMutableDictionary (JSONRepresentation) 创建 JSON 请求。

// My code    

NSArray *keysEndpoint = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint = [NSArray arrayWithObjects:@"622", @"Brand", @"0", nil];

NSArray *keysEndpoint1 = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint1 = [NSArray arrayWithObjects:@"595", @"CK-05052011", @"1", nil];

NSMutableArray *keys1 = [[NSMutableArray alloc] initWithCapacity:0];
NSMutableArray *objects1 =  [[NSMutableArray alloc] initWithCapacity:0];

[keys1 addObjectsFromArray:keysEndpoint];
[keys1 addObjectsFromArray:keysEndpoint1];

NSLog(@"Key Dic: %@", keys1);

[objects1 addObjectsFromArray:objectEndpoint];
[objects1 addObjectsFromArray:objectEndpoint1];

NSLog(@"Obje Dic: %@", objects1);

NSMutableDictionary *testMut = [NSMutableDictionary dictionaryWithObjects:objects1  forKeys:keys1];

NSLog(@"Test Dic: %@", testMut);

我得到的输出是这样的：

 Test Dic: {
    EndpointType = 1;
    ID = 595;
    Name = "CK-05052011";
}

我想要的Expexted输出是：

Test Dic: {
    EndpointType = 1;
    ID = 595;
    Name = "CK-05052011";
} 
{
    EndpointType = 0;
    ID = 622;
    Name = "Brand";
}

Answer 1

对于字典，添加相同的键两次将覆盖第一组键。你应该有一个 NSMutableArray 的 NSMutableDictionary

NSArray *keysEndpoint = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint = [NSArray arrayWithObjects:@"622", @"Brand", @"0", nil];

NSArray *keysEndpoint1 = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint1 = [NSArray arrayWithObjects:@"595", @"CK-05052011", @"1", nil];

NSMutableDictionary *testMut = [NSMutableDictionary dictionaryWithObjects:objectsEndpoint  forKeys:keysEndpoint];


NSMutableDictionary *testMut1 = [NSMutableDictionary dictionaryWithObjects:objectsEndpoint1  forKeys:keysEndpoint1];

NSMutableArray * dictArray = [NSMutableArray arrayWithObjects:testMut,testMut1,nil];

NSLog(@"Test DictArray: %@", dictArray);