Google 地图地理编码器：返回 postal_code

发布于 2024-12-19 18:06:46 字数 1077 浏览 1 评论 0原文

我正在使用 Jquery UI 使用 Google 地图地理编码器自动完成地址搜索，当选择一个地址时，它会返回地理编码信息。这是片段：

$('#address-dropdown').autocomplete({
  //Use geocoder to fetch lat+long values from an address input using google maps API
  source: function(request, response) {
    geocoder.geocode( {'address': request.term }, function(results, status) {
      response($.map(results, function(item) {
        return {
          label: item.formatted_address,
          value: item.formatted_address,
          location: item.geometry.location,
          latitude: item.geometry.location.lat(),
          longitude: item.geometry.location.lng()
        }
      }));
    })
  },

我需要能够返回用户“postal_code”以检查它们是否居住在允许的区域内。以下是示例输出：http://maps.googleapis.com/maps/api/geocode/json?address=1601+Main+St+Eaton+Rapids+MI+48864&sensor=false

我怎么能目标邮政编码信息？

原文

I'm using Jquery UI to autocomplete search for an address using Google Maps Geocoder, and when an address is selected it returns the geocode information. Here is the snippet:

$('#address-dropdown').autocomplete({
  //Use geocoder to fetch lat+long values from an address input using google maps API
  source: function(request, response) {
    geocoder.geocode( {'address': request.term }, function(results, status) {
      response($.map(results, function(item) {
        return {
          label: item.formatted_address,
          value: item.formatted_address,
          location: item.geometry.location,
          latitude: item.geometry.location.lat(),
          longitude: item.geometry.location.lng()
        }
      }));
    })
  },

I need to ability to return the uses "postal_code" to check if they live within an allowable area. Here is an example output: http://maps.googleapis.com/maps/api/geocode/json?address=1601+Main+St+Eaton+Rapids+MI+48864&sensor=false

How could I target the postal_code information?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

哭泣的笑容 2024-12-26 18:06:47

看我的例子： http://jsfiddle.net/nEKMK/

o 是你的对象。

if (o.results[0].address_components) {
    for (var i in o.results[0].address_components) {
        if (typeof(o.results[0].address_components[i]) === "object" && o.results[0].address_components[i].types[0] == "postal_code") {
            var result = o.results[0].address_components[i].long_name;
        }
    }
}
if (!result) {
    alert("Error, there is no postal code");
} else {
   alert(result);
}

Look at my example: http://jsfiddle.net/nEKMK/

o is your object.

if (o.results[0].address_components) {
    for (var i in o.results[0].address_components) {
        if (typeof(o.results[0].address_components[i]) === "object" && o.results[0].address_components[i].types[0] == "postal_code") {
            var result = o.results[0].address_components[i].long_name;
        }
    }
}
if (!result) {
    alert("Error, there is no postal code");
} else {
   alert(result);
}

回复收藏 0 原文

~没有更多了~