在 iOS 上将 wchar_t* 转换为 char*
我正在尝试将 wchar_t* 转换为 char*。这是我的代码：
size_t result = wcstombs(returned, str, length + 1);
if (result == (size_t)-1) {
int error = errno;
}
它确实失败了，错误填充为 92 (ENOPROTOOPT) - 协议不可用。
我什至尝试过设置区域设置：
setlocale(LC_ALL, "C");
还有这个：
setlocale(LC_ALL, "");
我很想用静态转换来抛出角色！
I'm attempting to convert a wchar_t* to a char*. Here's my code:
size_t result = wcstombs(returned, str, length + 1);
if (result == (size_t)-1) {
int error = errno;
}
It indeed fails, and error is filled with 92 (ENOPROTOOPT) - Protocol not available.
I've even tried setting the locale:
setlocale(LC_ALL, "C");
And this one too:
setlocale(LC_ALL, "");
I'm tempted to just throw the characters with static casts!
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似乎问题在于源字符串是使用非标准编码（每个宽字符两个 ASCII 字符）进行编码的，这在调试器中看起来很好，但显然在内部很糟糕。生成的错误代码显然没有记录，但这相当于无法解码所述文本。
Seems the issue was that the source string was encoded with a non-standard encoding (two ASCII characters for each wide character), which looked fine in the debugger, but clearly internally was sour. The error code produced is clearly not documented, but it's the equivalent to simply not being able to decode said piece of text.