nsindexpath 访问行到节属性会导致 SIGABRT？

发布于 2024-12-19 10:00:14 字数 726 浏览 5 评论 0原文

针对 iOS 5.0，当我尝试在以下代码中访问 NSIndexPath 对象的行或部分属性时，我看到 SIGABRT：

NSIndexPath* path = [[NSIndexPath alloc] initWithIndex:0];
int row = path.row; //SIGABRT
int section = path.section;//SIGABRT

此示例建议使用 indexPathWithIndex: 相反 http://developer.apple.com/library/mac/#samplecode/SourceView/Listings/BaseNode_m.html#//apple_ref/doc/uid/DTS10004441-BaseNode_m-DontLinkElementID_6

path = [NSIndexPath indexPathWithIndex:0];

结果保持一致。有谁能解释为什么会发生这种情况？难道iOS 5.0中我们就不能操作NSIndexPath了吗？

提前致谢。

原文

Targeting iOS 5.0 I see SIGABRT when I try to access row or section properties of NSIndexPath object in the following code:

NSIndexPath* path = [[NSIndexPath alloc] initWithIndex:0];
int row = path.row; //SIGABRT
int section = path.section;//SIGABRT

This example suggests using indexPathWithIndex: instead http://developer.apple.com/library/mac/#samplecode/SourceView/Listings/BaseNode_m.html#//apple_ref/doc/uid/DTS10004441-BaseNode_m-DontLinkElementID_6

path = [NSIndexPath indexPathWithIndex:0];

The results remain consistent. Does anyone have an explanation of why this might happen? Is it that we just cannot operate on NSIndexPath in iOS 5.0?

Thanks in advanced.

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阳光①夏 2024-12-26 10:00:14

尝试使用 indexPathForRow:inSection: 创建索引路径

NSIndexPath* path = [NSIndexPath indexPathForRow:0 inSection:0];

Try creating the index path using indexPathForRow:inSection:

NSIndexPath* path = [NSIndexPath indexPathForRow:0 inSection:0];

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活泼老夫 2024-12-26 10:00:14

我唯一能想到的就是确保您将 UIKit.framework 作为您的框架之一。您可以通过按目标上“构建阶段”下的“链接二进制文件与库”部分中的加号按钮来完成此操作。另外，请确保在尝试访问索引路径的文件中导入 NSIndexPath.h 。

我以前遇到过这个问题，这解决了它。这是因为虽然 NSIndexPath 在 Cocoa 和 CocoaTouch 之间是通用的，但 Cocoa 版本没有属性 row 和 section。

如果您已经有 UIKit.framework，请尝试使用 [NSIndexPath indexPathForRow:row inSection:section] 而不是 [NSIndexPath indexPathWithIndex:index]。

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走过海棠暮 2024-12-26 10:00:14

我认为问题在于 indexPathWithIndex: 创建一个单节点索引路径。与 initWithIndex: 相同。部分和行属性来自 UITableView 类别到 NSIndexPath 类。单节点索引路径对于与表视图一起使用无效，因为传递给表视图的索引路径必须包含两个指定节和行的索引（根据我运行代码时收到的错误消息）。以下代码创建一个具有两个索引的索引路径，并且运行时不会抛出 NSInternalInconsistencyException：

NSUInteger x[] = {0 , 0};
NSIndexPath *path = [[NSIndexPath alloc] initWithIndexes: x length: 2];
int row = [path row];
int section = [path section];
row = path.row;
section = path.section;

这就是您所说的“在 iOS 5.0 中对 NSIndexPath 进行操作”的意思吗？

I think the problem is that indexPathWithIndex: creates a one-node index path. Same for initWithIndex:. The section and row properties come from the UITableView category to the NSIndexPath class. A one-node index path is invalid for use with a table view because index paths passed to table views must contain two indices specifying the section and row (according to the error message I get when I run your code). The following code creates an index path with two indices and runs without throwing an NSInternalInconsistencyException:

NSUInteger x[] = {0 , 0};
NSIndexPath *path = [[NSIndexPath alloc] initWithIndexes: x length: 2];
int row = [path row];
int section = [path section];
row = path.row;
section = path.section;

Is this what you meant by "operate on NSIndexPath in iOS 5.0"?

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