杀死进程的 shell 脚本

发布于 2024-12-19 09:50:42 字数 274 浏览 0 评论 0原文

我需要实现一个终止进程的 shell 脚本。问题是我需要执行一个条件才能查看进程是否正在运行。

这是我的代码，但它不起作用：

#!/bin/sh

if [ -x  "MY_PROCCESS_NAME"]; then
    killall MY_PROCCESS_NAME
else
    echo "Doesn't exist"
fi

这是错误：

line 3: [: missing `]'

原文

I need to implement a shell script that kills a process. The problem is that I need to do a conditional to be able to see if the process is running or not.

This is my code, but it is not working:

#!/bin/sh

if [ -x  "MY_PROCCESS_NAME"]; then
    killall MY_PROCCESS_NAME
else
    echo "Doesn't exist"
fi

This is the error:

line 3: [: missing `]'

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那支青花 2024-12-26 09:50:42

要检查进程是否在 mac os x 上运行，您可以使用：

pid=$(ps -fe | grep 'process name' | grep -v grep | awk '{print $2}')

如果您想减少 shell 脚本的数量，您可以将进程名称的字符之一括在方括号中：

pid=$(ps -fe | grep '[p]rocess name' | awk '{print $2}')

结合在您的测试中，这看起来像：

pid=$(ps -fe | grep '[p]rocess name' | awk '{print $2}')
if [[ -n $pid ]]; then
    kill $pid
else
    echo "Does not exist"
fi

这比在 Linux 下需要做的要复杂一些，因为通常有“pgrep”命令，它大致相当于“ps -fe |” | grep ... | grep -v grep'

to check if a process is running on mac os x you can use:

pid=$(ps -fe | grep 'process name' | grep -v grep | awk '{print $2}')

if you want to reduce the number of shell scripts you can enclose one of the characters of the name of the process in square brackets:

pid=$(ps -fe | grep '[p]rocess name' | awk '{print $2}')

combined in your test this would look like:

pid=$(ps -fe | grep '[p]rocess name' | awk '{print $2}')
if [[ -n $pid ]]; then
    kill $pid
else
    echo "Does not exist"
fi

it's a little more complicated than you would need to do under linux as you generally have the 'pgrep' command, which is the rough equivalent of the 'ps -fe | grep ... | grep -v grep'

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