HttpPost URI 不完整

发布于 2024-12-19 08:04:51 字数 933 浏览 0 评论 0原文

我想从链接获取 json 信息： http://android.forum-example.org/?a=1&b=2&c=3

但 Log.v 告诉我，在请求之后.setEntity(new UrlEncodedFormEntity(qparams)); 我的 URI 是：http://android.forum-example.org/?

我的错误在哪里？

代码：

try {
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost request = new HttpPost("http://android.forum-example.org/?");
    List<NameValuePair> qparams = new ArrayList<NameValuePair>(3);
    qparams.add(new BasicNameValuePair("a", "1"));
    qparams.add(new BasicNameValuePair("b", "2"));
    qparams.add(new BasicNameValuePair("c", "3"));
    request.setEntity(new UrlEncodedFormEntity(qparams));
    Log.v("URI:", request.getURI().toString());
    HttpResponse response = httpClient.execute(request);
    } catch (IOException e) { e.printStackTrace(); }

原文

I want to get json info from the link:
http://android.forum-example.org/?a=1&b=2&c=3

but Log.v tells me that after request.setEntity(new UrlEncodedFormEntity(qparams));
my URI is: http://android.forum-example.org/?

Where is my mistake?

code:

try {
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost request = new HttpPost("http://android.forum-example.org/?");
    List<NameValuePair> qparams = new ArrayList<NameValuePair>(3);
    qparams.add(new BasicNameValuePair("a", "1"));
    qparams.add(new BasicNameValuePair("b", "2"));
    qparams.add(new BasicNameValuePair("c", "3"));
    request.setEntity(new UrlEncodedFormEntity(qparams));
    Log.v("URI:", request.getURI().toString());
    HttpResponse response = httpClient.execute(request);
    } catch (IOException e) { e.printStackTrace(); }

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单身情人 2024-12-26 08:04:51

您正在尝试发出 POST 请求..但 url 的类型为 GET 请求

请查看此处：如何在 Android 中向 HTTP GET 请求添加参数？

回复收藏 0 原文

当梦初醒 2024-12-26 08:04:51

使用 HttpGet 而不是 HttpPost：

try {
    HttpClient httpClient = new DefaultHttpClient();
    HttpGet request = new HttpGet("http://android.forum-example.org/?a=1&b=2&c=3");
    Log.v("URI:", request.getURI().toString());
    HttpResponse response = httpClient.execute(request);
} catch (IOException e) {
    e.printStackTrace();
}

Use HttpGet instead of HttpPost:

try {
    HttpClient httpClient = new DefaultHttpClient();
    HttpGet request = new HttpGet("http://android.forum-example.org/?a=1&b=2&c=3");
    Log.v("URI:", request.getURI().toString());
    HttpResponse response = httpClient.execute(request);
} catch (IOException e) {
    e.printStackTrace();
}

回复收藏 0 原文

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