Java - 自定义油漆声明性能
快速是，不是，或者这并不重要：
我正在重写抽象按钮的绘制方法，我想知道这样做
GradientPaint gp = new GradientPaint(0, 0, color1, 0, h, color2);
RoundRectangle2D r = new RoundRectangle2D.Float(0, 0, w, h, w/5, h/5);
和类似的方法是否会影响性能与
GradientPaint gp;
RoundRectangle2D r;
外部绘制然后
gp = new GradientPaint(0, 0, color1, 0, h, color2);
r = new RoundRectangle2D.Float(0, 0, w, h, w/5, h/5);
在绘制方法内部的性能
Quick yes, no, or it doesn't really matter:
I'm overriding the paint method for an abstract button and I'm wondering if doing
GradientPaint gp = new GradientPaint(0, 0, color1, 0, h, color2);
RoundRectangle2D r = new RoundRectangle2D.Float(0, 0, w, h, w/5, h/5);
and similar methods are going to affect performance vs
GradientPaint gp;
RoundRectangle2D r;
outside paint and then
gp = new GradientPaint(0, 0, color1, 0, h, color2);
r = new RoundRectangle2D.Float(0, 0, w, h, w/5, h/5);
inside the paint method
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评论（3）
杰里米怎么样了？
不是你要问的，但最快的可能是在 BufferedImage 中绘制一次，然后在 Paint （或者可能更好的 PaintComponent）方法中显示 BufferedImage。
How's it going Jeremy?
Not what you're asking, but quickest of all would likely be to do the drawing once in a BufferedImage, and then display the BufferedImage in the paint (or perhaps better paintComponent) method.
实例化它们一次或在必要时（例如大小更改）而不是多次。
Instantiate them once or when necessary (e.g. size change) rather than many times.
寻求最可维护的解决方案，直到你衡量问题:-)
每个“优化”都需要额外的逻辑（又名：LOC）。每增加一条线路都有一个难以预测的维护成本。我的一般规则是不会增加无法计算的成本。
顺便说一句：无论如何你都不能做你的第一个选择，渐变是不可变的 - 所以你必须在每次大小改变时重新创建。
Go for the most maintainable solution until you measure problems :-)
Every "optimization" requires additional logic (aka: LOC). Each additional line has a - difficult to predict - price in maintenance. My general rule it not add uncalculatable costs.
BTW: you can't do your first option anyway, gradients are immutable - so you have to recreate each time the size has changed.