iphone数组与字典的索引

发布于 2024-12-19 03:42:42 字数 403 浏览 4 评论 0原文

我有一个带有字典的数组，

.如何获取特定字典的索引...[我在其中获取了我想要查找的字典的数据，但需要打开索引]

NSMutableDictionary *dictois = [[NSMutableDictionary alloc]init];
[dictois setObject:@"easySpritedd" forKey:@"Nombre"];
[dictois setObject:@"X" forKey:@"290"];
[dictois setObject:@"Y" forKey:@"300"];

int fooIndex = [self.bloquesArray indexOfObject: dictois];

但正如你所见，我还不知道如何获取字典以在对象索引

谢谢！

原文

i have an array with dictionaries,

. how to get the index for a specific dictionary... [where I got the data for the dictionary i want to find, but need the index is on]

NSMutableDictionary *dictois = [[NSMutableDictionary alloc]init];
[dictois setObject:@"easySpritedd" forKey:@"Nombre"];
[dictois setObject:@"X" forKey:@"290"];
[dictois setObject:@"Y" forKey:@"300"];

int fooIndex = [self.bloquesArray indexOfObject: dictois];

but as you see i dont know yet how to get the dictionary for comparing in the indexOfObject

thanks!

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乖乖公主 2024-12-26 03:42:42

NSDictionary对象有以下比较方法：

- (BOOL)isEqualToDictionary:(NSDictionary *)otherDictionary

有以下讨论

如果两个字典包含相同的数字，则它们具有相同的内容
的条目，以及对于给定的键，相应的值对象
每个字典都满足 isEqual: 测试。

您应该属于这种情况。遗憾的是，您无法更改 NSArray 用于计算 indexOfObject 的方法：因此它无法帮助您，因此 Denis 提供的解决方案是我能想到的最好的解决方案（除非您喜欢子类化 NSArray，但我不推荐）。

作为对 Denis 答案的补充，您可以使用 NSArray 方法

- (NSIndexSet *)indexesOfObjectsPassingTest:(BOOL (^)(id obj, NSUInteger idx, BOOL *stop))predicate

而不是

- (NSUInteger)indexOfObjectPassingTest:(BOOL (^)(id obj, NSUInteger idx, BOOL *stop))predicate

如果数组中有多个相等的对象是可能的。

NSDictionary objects have the following comparison methods:

- (BOOL)isEqualToDictionary:(NSDictionary *)otherDictionary

With the following discussion

Two dictionaries have equal contents if they each hold the same number
of entries and, for a given key, the corresponding value objects in
each dictionary satisfy the isEqual: test.

This should be the case for you. Sadly you cannot change the method which NSArray uses to calculate the indexOfObject: so it can't help you, hence the solution provided by Denis is the best I can think of (unless you fancy subclassing NSArray which I wouldn't recommend).

Just as a complement to Denis' answer you could use the NSArray method

- (NSIndexSet *)indexesOfObjectsPassingTest:(BOOL (^)(id obj, NSUInteger idx, BOOL *stop))predicate

instead of

- (NSUInteger)indexOfObjectPassingTest:(BOOL (^)(id obj, NSUInteger idx, BOOL *stop))predicate

If having several equal objects in the array is a possibility.

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同尘 2024-12-26 03:42:42

使用以下代码

NSMutableDictionary *dictois = [[NSMutableDictionary new]autorelease];

[dictois setObject:@"easySpritedd" forKey:@"Nombre"];
[dictois setObject:@"X" forKey:@"290"];
[dictois setObject:@"Y" forKey:@"300"];

int fooIndex = [self.bloquesArray indexOfObjectPassingTest: ^(id obj, NSUInteger idx, BOOL *stop){
  if( [[obj class] isKindOfClass: [NSDictionary class]] ) {
    BOOL result = [obj isEqualToDictionary: diction];
    *stop = result;
    return result;
  }

  *stop = NO;
  return NO;

}];

Use the following code

NSMutableDictionary *dictois = [[NSMutableDictionary new]autorelease];

[dictois setObject:@"easySpritedd" forKey:@"Nombre"];
[dictois setObject:@"X" forKey:@"290"];
[dictois setObject:@"Y" forKey:@"300"];

int fooIndex = [self.bloquesArray indexOfObjectPassingTest: ^(id obj, NSUInteger idx, BOOL *stop){
  if( [[obj class] isKindOfClass: [NSDictionary class]] ) {
    BOOL result = [obj isEqualToDictionary: diction];
    *stop = result;
    return result;
  }

  *stop = NO;
  return NO;

}];

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