unsigned char 类型变量的 I/O 失败

发布于 2024-12-19 02:10:03 字数 693 浏览 4 评论 0原文

我有一个名为 input.in 的文件。我需要读取该数字并将其存储在无符号字符类型变量中。我读入数字并在屏幕上打印变量的内容，我可以看到它是 true（打印 1）。但是，if 语句失败。它将 False 打印到标准输出。为什么会出现这种情况？如何将此数字存储到 unsigned char 变量中？

input.in 文件：

asus@ubuntu:~/Desktop$ cat input.in 
1

我在 Ubuntu 上工作。 sizeof(无符号字符)=1

#include <fstream>
#include <iostream>

using namespace std;

int main(){

    unsigned char ucbuffer;

    fstream in;

    in.open("input.in",ios::binary | ios::in);

    in.read((char*)&ucbuffer,1);

    cout << ucbuffer << endl;
    if (ucbuffer==1) cout << "True" << endl;
    else cout << "False" << endl;

        return 0;
}

原文

I have a file named input.in. I need to read the number and store it in an unsigned char typed variable. I read in the number and print the content of the variable on the screen and I can see it's true(prints 1). However, the if statement fails. It prints False to the stdout. Why does this happen? How can I store this number into an unsigned char variable?

The input.in file:

asus@ubuntu:~/Desktop$ cat input.in 
1

I work on Ubuntu. sizeof(unsigned char)=1

#include <fstream>
#include <iostream>

using namespace std;

int main(){

    unsigned char ucbuffer;

    fstream in;

    in.open("input.in",ios::binary | ios::in);

    in.read((char*)&ucbuffer,1);

    cout << ucbuffer << endl;
    if (ucbuffer==1) cout << "True" << endl;
    else cout << "False" << endl;

        return 0;
}

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