将用户输入到列表中

发布于 2024-12-19 01:10:42 字数 445 浏览 0 评论 0原文

我正在尝试接收用户输入，然后将其放入列表中。我有一个工作版本，但是，我觉得它好像是多余的（第一个块似乎是多余的，但如果我把它拿走，它就不起作用）。有什么办法可以改善这种情况吗？感谢

def pastChoice():
     choice = raw_input("> ")
     prevMove = []
     prevMove.append(choice)

for i in prevMove:
     choice = raw_input("> ")
     prevMove.append(choice)
     print prevMove

PastChoice()

我正在制作一个游戏，我想向用户展示他们已经做出的选择。

前任。如果您想查看以前的选择，请输入“history”

['a','a','c','b']

原文

I am trying to receive user input and then put it into a list. I have a working version, however, I feel as though it is redundant(the first block seems redundant, though if I take it away, it doesn't work). Any way this can be improved?
Thanks

def pastChoice():
     choice = raw_input("> ")
     prevMove = []
     prevMove.append(choice)

for i in prevMove:
     choice = raw_input("> ")
     prevMove.append(choice)
     print prevMove

pastChoice()

I am making a game and I want to show the user what choices they have already made.

Ex. Type 'history' if you would like to see previous choices

['a','a','c','b']

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巴黎盛开的樱花 2024-12-26 01:10:42

我不确定您对此代码的意图，但这大致相同：

def pastChoice():
    prevMove = []

    while True:
        choice = raw_input("> ")
        prevMove.append(choice)
        print prevMove
pastChoice()

块：

 choice = raw_input("> ")
 prevMove = []
 prevMove.append(choice)

要求用户输入并将其附加到 prevMove，因此在循环开始时，条件 i in prevMove 评估 < code>i 到 prevMove 中的第一个元素，然后因为在第二个块中您将新元素附加到 prevMove，所以迭代会继续对新元素进行迭代附加元素和循环永远不会结束。

如果删除第一个块，但保留 for 循环，则它将不起作用，因为 prevMove 内没有元素，因此没有可迭代的内容。

I'm not sure about your intentions for this code, but this is roughly equivalent:

def pastChoice():
    prevMove = []

    while True:
        choice = raw_input("> ")
        prevMove.append(choice)
        print prevMove
pastChoice()

the block:

 choice = raw_input("> ")
 prevMove = []
 prevMove.append(choice)

asks user for input and appends it to prevMove, so at loop start, the condition i in prevMove evaluates i to the first element in prevMove, then because in the second block you're appending new elements to prevMove, the iteration continues over those the newly appended elements and the loop never ends.

If you remove the first block, but keep the for loop, it won't work because there are no elements inside prevMove and therefore nothing to iterate over.

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几味少女 2024-12-26 01:10:42

你可以这样做吗？我不知道你尝试这样做的真正原因，但是接受用户输入并添加到列表中就可以了。

def main():
     prevMove = []
     choice = ''

     def getHistory():
          print prevMove

     while True:
          choice = raw_input("> ")
          if choice == '':
               break
          prevMove.append(choice)
          # do whatever you want with the input here

          # a call to history
          getHistory()

if __name__ == "__main__":
     main()

编辑：

由于问题编辑，代码现在将记录事件的历史记录并具有获取它们的功能。

you could do it this way? I don't know the real reason you are trying to do this, but to accept user input and add to a list this will do fine.

def main():
     prevMove = []
     choice = ''

     def getHistory():
          print prevMove

     while True:
          choice = raw_input("> ")
          if choice == '':
               break
          prevMove.append(choice)
          # do whatever you want with the input here

          # a call to history
          getHistory()

if __name__ == "__main__":
     main()

EDIT:

Due to Questions edit, the code will now record the history of events and have a function to obtain them.

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