可拖放功能

Question

假设我的左侧有一些可放置的 div，标题为区域 1 - 4。右侧有一些

<div id="zone1"></div>
<div id="zone2"></div>
<div id="zone3"></div>
<div id="zone4"></div>

可拖动的项目，

<div id="drag1">Apple</div>
<div id="drag2">Banana</div>
<div id="drag3">Kiwi</div>
<div id="drag4">Orange</div>

我知道我可以将它们设置为可拖动和可放置，如下所示：

for (var i=1;i<=4;i++)
{
   var x = "zone" + i;
   $(x).droppable();
}
  for (var i=1;i<=4;i++)
{
   var x = "drag" + i;
   $(x).draggable();
}

现在我将如何触发当水果掉落在某个区域时启动的函数，该函数将告诉我掉落的位置（区域 1、区域 2 等）以及掉落的水果。理想情况下，我不需要水果名称，我想要一个与水果相关联的ID，可能隐藏在隐藏的输入标签或其他东西中？

Answer 1

我建议你这样做，而不是你现有的。

<div id="zone1" class="droppable"></div>
<div id="zone2" class="droppable"></div>
<div id="zone3" class="droppable"></div>
<div id="zone4" class="droppable"></div>

<div id="drag1" class="draggable">Apple</div>
<div id="drag2" class="draggable">Banana</div>
<div id="drag3" class="draggable">Kiwi</div>
<div id="drag4" class="draggable">Orange</div>

然后是你的脚本：

var fruit_id = '';
var dropbox_id = '';
$( '.draggable' ).draggable();
$( '.droppable' ).droppable({
               drop: function( event, ui ) {
            fruit_id = $(ui.draggable).attr('id');
                            dropbox_id = $( this ).attr('id');
                            /* DO SOMETHING HERE */
        }
});
/* Or do something here! */

希望有帮助！

Answer 2

本教程中的示例

$(init)

function init() {
  $('#makeMeDraggable').draggable();
  $('#makeMeDroppable').droppable( {
    drop: handleDropEvent
  } );
}

function handleDropEvent( event, ui ) {
  var draggable = ui.draggable;
  alert( 'The square with ID "' + draggable.attr('id') + '" was dropped onto me!' );
}

Answer 3

您可以使用 droppable 交互的 drop 事件。在此事件处理程序中，$(this) 指向可放置元素，其中 ui.draggable 指向可拖动元素。

for (var i=1;i<=4;i++)
{
   var x = "zone" + i;
   $(x).droppable({
      drop: function(){
          //This will alert the id of container in which fruit is dropped
          alert($(this).attr('id'));

          //This will alert the id of fruit container which is dragged
          alert($(ui.draggable).attr('id'));
      }
   });
}
  for (var i=1;i<=4;i++)
{
   var x = "drag" + i;
   $(x).draggable();
}

Answer 4

<style>
.zones>div{ border:solid 1px gray; background-color:yellow; padding:20px;margin:5px;}
</style>

<div class="zones">
    <div id="zone1"></div>
    <div id="zone2"></div>
    <div id="zone3"></div>
    <div id="zone4"></div>
</div>


<div id="drag1" fruitid="1">Apple</div>
<div id="drag2" fruitid="2">Banana</div>
<div id="drag3" fruitid="3">Kiwi</div>
<div id="drag4" fruitid="4">Orange</div>

<script>

$("div[id*='zone']").droppable({
            accept: "div[id*='drag']",
            drop: function( event, ui ) {
                alert( ui.draggable.text() + " with fruitid = "+ ui.draggable.attr("fruitid")+" added to " + $(this).attr("id"));
                  $( "<div/>" ).text( ui.draggable.text()).appendTo( this );
            }
        })
$('div[id*="drag"]').draggable({helper: "clone"});

</script>