JavaScript:onmouseover 函数
我在更改动态图片上的 onmouseover 和 onmouseout 属性时遇到问题。我希望它的工作方式是,每当我将鼠标放在图像上时,图像都必须更改,当我将鼠标移开时,图像必须更改为原始图片。每当我选择任何图像时,该图像都必须更改为在图像上移动鼠标时显示的图像。当我选择任何其他图像时,必须进行相同的过程,但之前更改的图像必须更改回原始图片。
我已经完成了上述所有操作,但我的问题是,当我选择多张图片并将鼠标放在之前选择的图像上时,这些图像不会更改(onmouseover 属性不再对它们起作用)。
<script language="javascript">
function changeleft(loca){
var od=''
var imgs = document.getElementById("leftsec").getElementsByTagName("img");
for (var i = 0, l = imgs.length; i < l; i++) {
od=imgs[i].id;
if(od==loca){
imgs[i].src="images/"+od+"_over.gif";
imgs[i].onmouseover="";
imgs[i].onmouseout="";
}else{
od = imgs[i].id;
imgs[i].src="images/"+od+".gif";
this.onmouseover = function (){this.src="images/"+od+"_over.gif";};
this.onmouseout = function (){this.src="images/"+od+".gif";};
}
}
}
</script>
<div class="leftsec" id="leftsec" >
<img id='wits' class="wits1" src="images/wits.gif" onmouseover="this.src='images/wits_over.gif'" onmouseout="this.src='images/wits.gif'" onclick="changeleft(this.id)" /><br />
<img id='city' class="city1" src="images/city.gif" onmouseover="this.src='images/city_over.gif'" onmouseout="this.src='images/city.gif'" onclick="changeleft(this.id)" /><br />
<img id='organise' class="city1" src="images/organise.gif" onmouseover="this.src='images/organise_over.gif'" onmouseout="this.src='images/organise.gif'" onclick="changeleft(this.id)" /><br />
<img id='people' class="city1" src="images/people.gif" onmouseover="this.src='images/people_over.gif'" onmouseout="this.src='images/people.gif'" onclick="changeleft(this.id)" /><br />
</div>
I have a problem with changing onmouseover and onmouseout attributes on dynamic pictures. The way i want it to work is whenever i put my mouse over images the images must change and when i take my mouse away it must be changed to the original picture. and whenever i select any image, that image must be changed to the image which was displayed while moving the mouse across the image. and when i select any other image the same process must take place but the previous image that was changed must be changed back to the original picture.
I have accomplished all of the above but my problem is when i select multiple pictures and put my mouse over images that were previously selected, those images do not change (onmouseover attribute does not work on them anymore).
<script language="javascript">
function changeleft(loca){
var od=''
var imgs = document.getElementById("leftsec").getElementsByTagName("img");
for (var i = 0, l = imgs.length; i < l; i++) {
od=imgs[i].id;
if(od==loca){
imgs[i].src="images/"+od+"_over.gif";
imgs[i].onmouseover="";
imgs[i].onmouseout="";
}else{
od = imgs[i].id;
imgs[i].src="images/"+od+".gif";
this.onmouseover = function (){this.src="images/"+od+"_over.gif";};
this.onmouseout = function (){this.src="images/"+od+".gif";};
}
}
}
</script>
<div class="leftsec" id="leftsec" >
<img id='wits' class="wits1" src="images/wits.gif" onmouseover="this.src='images/wits_over.gif'" onmouseout="this.src='images/wits.gif'" onclick="changeleft(this.id)" /><br />
<img id='city' class="city1" src="images/city.gif" onmouseover="this.src='images/city_over.gif'" onmouseout="this.src='images/city.gif'" onclick="changeleft(this.id)" /><br />
<img id='organise' class="city1" src="images/organise.gif" onmouseover="this.src='images/organise_over.gif'" onmouseout="this.src='images/organise.gif'" onclick="changeleft(this.id)" /><br />
<img id='people' class="city1" src="images/people.gif" onmouseover="this.src='images/people_over.gif'" onmouseout="this.src='images/people.gif'" onclick="changeleft(this.id)" /><br />
</div>
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我建议使用 Ajax 库(jQuery、YUI、dojo、ExtJS,...)。在 jQuery 中,我会执行以下操作:
编辑: 使用
.click()
功能扩展示例。我认为有了库,它会更干净、更可扩展,而且它在其他浏览器中工作的机会也增加了:)。
希望这对您有帮助!
I would recommend to use an Ajax library (jQuery, YUI, dojo, ExtJS, ...). In jQuery I would do something like:
Edit: Extended the example with
.click()
ability.With a library it's cleaner and more scalable I think and the chance that it's working in other browsers is increased too :).
Hope this helps you out!