如何检查 Fortran 数组是否包含值？
我见过这要求其他语言，但刚刚发现 Fortran 可以很好地处理数组，我认为可能有一种简单的方法可以在没有循环的情况下做到这一点。
目前，我正在搜索一个 3D 数组，查看“最近的邻居”，看看它们是否包含字母“n”，每当它找到这个值时，我希望它执行一些 clusterLabel 分配（这与这个问题无关） ）
我想使用 if(lastNeighArray.eq."n") then...<其余代码> 但由于显而易见的原因，它不喜欢根据值检查数组。它也不喜欢我使用 lastNeighArray(:)，尽管我希望它一次检查每个元素。 where(lastNeighArray.eq."n") 不起作用，因为我在 where 循环内有一个 case 语句，并且收到错误 WHERE 语句和构造不得嵌套。代码>
所以我有点卡住了。我真正想要的是类似于 when(lastNeighArray.eq."n") 但那不存在。
我还查看了 any 和 forall 但它们似乎不是正确的选择。
I've seen this asked for other languages, but having just found out how nicely Fortran can handle arrays, I thought there might be an easy way to do this without loops.
Currently I'm searching over a 3D array looking at 'nearest neighbours' to see if they contain the letter 'n', and whenever it finds this value, I want it to perform some clusterLabel assignment (which isn't relevant for this question)
I wanted to use if(lastNeighArray.eq."n") then...<rest of code>
but for obvious reasons it doesn't like checking an array against a value. Neither does it like me using lastNeighArray(:), even though I'd like it to check each of the elements one at a time. where(lastNeighArray.eq."n") doesn't work as I have a case statement inside the where loop and I get the error WHERE statements and constructs must not be nested.
So I'm a little stuck. What I really want is something like when(lastNeighArray.eq."n") but that doesn't exist.
I've also looked at any and forall but they don't seem like the right choice.
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ANY 实际上应该是正确的选择，
如果您希望整个数组包含该值，也可以选择 ALL。
ANY should actually be the right choice
there is also ALL if you wanted the whole array to contain that value.