Rpy2找不到函数

发布于 2024-12-18 15:34:39 字数 580 浏览 3 评论 0原文

我四处寻找错误无法找到函数“someFunction”，这似乎是一个常见错误，但是我没有发现任何与 Rpy2 有关的错误。我想从用 python 制作的矩阵制作热图。

def HeatMap(HeatData):
    RHeatMap = robjects.FloatVector([HeatData[i] for i in range(len(HeatData[:,1]))])
    HeatMap = robjects.r['matrix'](RHeatMap, nrow = len(HeatData[:,1]))
    robjects.r('HeatMap = %s' %HeatMap.r_repr())
    robjects.r('jsr.colors=colorRampPalette(c("green","black","red"),interpolate="linear")')
    robjects.r('heatmap(HeatMap, Rowv = NA, Colv = NA, col = topo.colors(100))')

该错误是由最后两行引起的，但在 RI 中这两个函数都没有问题。

谢谢

原文

I've looked around for the error could not find function "someFunction" it appears to be a common error, however I have not found any pertaining to Rpy2. I want to make a heat map from a matrix I made in python.

def HeatMap(HeatData):
    RHeatMap = robjects.FloatVector([HeatData[i] for i in range(len(HeatData[:,1]))])
    HeatMap = robjects.r['matrix'](RHeatMap, nrow = len(HeatData[:,1]))
    robjects.r('HeatMap = %s' %HeatMap.r_repr())
    robjects.r('jsr.colors=colorRampPalette(c("green","black","red"),interpolate="linear")')
    robjects.r('heatmap(HeatMap, Rowv = NA, Colv = NA, col = topo.colors(100))')

The error is caused by both of the last 2 lines however in R I have no problem with either function.

Thanks

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早乙女 2024-12-25 15:34:39

我在Python2.7和rpy2 2.1.9下对你的代码没有任何问题。

如果直接调用 R 函数而不是使用字符串会发生什么？

HeatMap = robjects.r['matrix'](RHeatMap, nrow = len(HeatData[:,1]))
robjects.r['heatmap'](HeatMap, Rowv = robjects.NA_Integer, Colv = robjects.NA_Integer, col = robjects.r['topo.colors'](100))

I do not have any problems with your code under Python2.7 and rpy2 2.1.9.

What happens if you call the R functions directly instead of using strings?

HeatMap = robjects.r['matrix'](RHeatMap, nrow = len(HeatData[:,1]))
robjects.r['heatmap'](HeatMap, Rowv = robjects.NA_Integer, Colv = robjects.NA_Integer, col = robjects.r['topo.colors'](100))

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