Python中嵌套在列表中的元组的任意顺序

发布于 2024-12-18 08:34:35 字数 605 浏览 2 评论 0原文

我有一个从 Solr 返回的元组列表，如下所示：

 [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]

请注意，不仅返回了第二个、第三个、第九个和第十一个电路。

我需要根据我的排序元组对其进行排序：

COURT_ORDER = (
    'Supreme Court',
    'First Circuit',
    'Second Circuit',
    'Third Circuit',
    'Fourth Circuit',
    ...and so on...,
)

排序后所需的输出将是：

 [('Second Circuit', 34), ('Third Circuit', 4), ('Ninth Circuit', 24), ('Eleventh Circuit', 2)]

是否有一种聪明的方法可以做到这一点？

（如果可能的话，这需要标记为“晒伤”标签，但由于缺乏积分，我无法创建它。）

原文

I have a list of tuples like the following that I'm getting back from Solr:

 [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]

Note that not only the second, third, ninth and eleventh circuits were returned.

I need to order this according to an ordering tuple I have that looks like this:

COURT_ORDER = (
    'Supreme Court',
    'First Circuit',
    'Second Circuit',
    'Third Circuit',
    'Fourth Circuit',
    ...and so on...,
)

The desired output, after sorting would be:

 [('Second Circuit', 34), ('Third Circuit', 4), ('Ninth Circuit', 24), ('Eleventh Circuit', 2)]

Is there a clever way of doing this?

(This needs to get tagged with the Sunburnt tag, if possible, but I can't create it, for lack of points.)

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筱武穆 2024-12-25 08:34:35

建立一个字典，将法院名称映射到所需的排名。然后使用关键函数进行排序，该函数查找法院名称以找到排名：

>>> COURT_ORDER = (
    'Supreme Court',
    'First Circuit',
    'Second Circuit',
    'Third Circuit',
    'Fourth Circuit',
    'Ninth Circuit',
    'Eleventh Circuit',
)
>>> court_seq = dict(zip(COURT_ORDER, range(len(COURT_ORDER))))
>>> lot = [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]
>>> sorted(lot, key=lambda t: court_seq[t[0]])
[('Second Circuit', 34), ('Third Circuit', 4), ('Ninth Circuit', 24), ('Eleventh Circuit', 2)]

有关如何排序的更多见解，请参阅排序 HOWTO。

Build a dictionary that maps the court name to the desired ranking. Then sort with a key function that looks up the court name to find the ranking:

>>> COURT_ORDER = (
    'Supreme Court',
    'First Circuit',
    'Second Circuit',
    'Third Circuit',
    'Fourth Circuit',
    'Ninth Circuit',
    'Eleventh Circuit',
)
>>> court_seq = dict(zip(COURT_ORDER, range(len(COURT_ORDER))))
>>> lot = [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]
>>> sorted(lot, key=lambda t: court_seq[t[0]])
[('Second Circuit', 34), ('Third Circuit', 4), ('Ninth Circuit', 24), ('Eleventh Circuit', 2)]

For more insights on how to sort, see the Sorting HOWTO.

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感情洁癖 2024-12-25 08:34:35

根据[0]项目在COURT_ORDER中首次出现的索引来key项目：

data = [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]
sorted(data, key = lambda x: COURT_ORDER.index(x[0]))

key the items according to the index of the first appearance of their [0] item in the COURT_ORDER:

data = [('Second Circuit', 34), ('Ninth Circuit', 24), ('Third Circuit', 4), ('Eleventh Circuit', 2)]
sorted(data, key = lambda x: COURT_ORDER.index(x[0]))

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