我应该如何使用 QM 建模工具实现正交组件
我了解如何编码正交组件，如下所述： http://www.state-machine .com/resources/Pattern_Orthogonal.pdf。我的问题是 QM 只允许每个活动对象有一个状态图。如何最好地对“组件”状态图进行建模，因为它与“容器”状态图位于同一活动对象中。
有接受者吗？
I understand how to code an orthogonal component as described here: http://www.state-machine.com/resources/Pattern_Orthogonal.pdf. My problem is that QM only allows one statechart per active object. How do I best model the "component" statechart seeing as it is in the same active object as the "container" statechart.
Any takers?
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您需要将组件建模为从 QHsm 或 QFsm 派生的单独类（它确实是）。其余部分如“正交分量”模式描述中所述。也就是说，您需要 (1) 将 Component 实例嵌入到 Container 中，(2) 从 Container 的最顶层初始转换触发 Component 的最顶层初始转换，以及 (3) 显式地将事件分派到成分。请记住，组件需要将事件（异步）发送到容器。
You need to model the Component as a separate class (which it really is) derived from QHsm or QFsm. The rest is as described in the "Orthogonal Component" pattern description. That is, you need to (1) embed the Component instance inside the Container, (2) trigger the top-most initial transition of the Component from the top-most initial transition of the Container, and (3) explicitly dispatch events to the Component. Please remember that the Component needs to post (asynchronously) the events to the Container.