定义一个实现可比较的接口
我试图定义一个接口，以便所有实现类都必须与它们自己及其子类进行比较。
例如，考虑：
public interface Rating implements Comparable<Rating> {}
这意味着实现类必须与所有评级相比较：
public class A implements Rating {
public int compareTo(Rating r) {return 0;}
}
我想放宽该要求，以便我可以定义一个类，例如：
public class A implements Rating {
public int compareTo(A a) {return 0;}
}
I'm trying to define an interface such that all implementing classes must be Comparable to themselves and their subclasses.
For example, consider:
public interface Rating implements Comparable<Rating> {}
This means that implementing classes must be Comparable to all Ratings:
public class A implements Rating {
public int compareTo(Rating r) {return 0;}
}
I'd like to loosen that requirement so that I can define a class like:
public class A implements Rating {
public int compareTo(A a) {return 0;}
}
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评论（2）
我希望您尝试得到这样的东西：
或者也许（虽然我不确定您能做到这一点）：
请参阅 Oracle 的此页面 了解有关有界通配符的更多信息。
I expect you're trying to get at something like this:
or maybe (although I'm not sure you can do this):
See this page at Oracle for more information on bounded wildcards.
我想你可能希望你的“compareTo()”返回除“0”之外的东西;)
您可以使用“instanceof”来查看任意对象是否是某个特定类（或子类）
I不确定是否超载“compareTo()”必然是个好主意。您甚至可能希望将输入参数设置为“Object o”。
恕我直言..pSM
I imagine you probably want your "compareTo()" to return something besides "0" ;)
You can use "instanceof" to see if an arbitrary object is some particular class (or a subclass)
I'm not sure overloading "compareTo()" is necessarily a good idea. You might even want to make the input argument "Object o".
IMHO .. pSM