如何跳过打开/关闭范围模式的记录？
gawk '/<Lexer>/,/<\/Lexer>/' file
这有效，但它打印第一条和最后一条记录，我想省略。怎么做呢？
它说：“打开范围模式的记录和关闭范围模式的记录都与范围模式匹配。如果不想对这些记录进行操作，可以在规则的操作中编写 if 语句以将它们与您感兴趣的记录。”但没有例子。 我尝试过类似的东西 gawk '/ 但它不起作用。 如果您有更好的方法来做到这一点，而不使用 awk，请说出来。
gawk '/<Lexer>/,/<\/Lexer>/' file
this works but it prints the first and last records, which I'd like to omit. How to do so?
It says: "The record that turns on the range pattern and the one that turns it off both match the range pattern. If you don't want to operate on these records, you can write if statements in the rule's action to distinguish them from the records you are interested in." but no example.
I tried something likegawk '/<Lexer>/,/<\/Lexer>/' {1,FNR-1} file
but it doesn't work.
If you have a better way to do this, without using awk, say so.
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您可以使用 2 个单独的匹配语句和一个变量
This matches
时，它将 p 设置为 0 并跳过。当 p 为 0 时，打印被抑制。You can do it with 2 separate match statements and a variable
This matches
<Lexer>and sets p to 1 and then skips to the next line. While p is 1 it prints the current line. When it matches</Lexer>it sets p to 0 and skips. As p is 0 printing is suppressed.