OpenStreetMap 点未显示在具有开放图层的地图上
var map;
var vectors;
var point;
var drag;
可以使用任何长和纬度
function mapCreate(lon,lat){
map = new OpenLayers.Map("map1");
var osm = new OpenLayers.Layer.OSM();
//create a vector
vectors = new OpenLayers.Layer.Vector("Vector Layer");
map.addLayer(osm);
var center = new OpenLayers.LonLat(lon,lat).transform(
new OpenLayers.Projection("EPSG:4326"),
map.getProjectionObject()
);
为该点指定一个纬度长
point = new OpenLayers.Geometry.Point(lat,lon);
将点添加到向量
vectors.addFeatures([new OpenLayers.Feature.Vector(point)]);
map.setCenter(center, 15);
//add vectors to map
map.addLayer(vectors);
}
我是否遗漏了什么？
var map;
var vectors;
var point;
var drag;
Any long and Lat can be used
function mapCreate(lon,lat){
map = new OpenLayers.Map("map1");
var osm = new OpenLayers.Layer.OSM();
//create a vector
vectors = new OpenLayers.Layer.Vector("Vector Layer");
map.addLayer(osm);
var center = new OpenLayers.LonLat(lon,lat).transform(
new OpenLayers.Projection("EPSG:4326"),
map.getProjectionObject()
);
Assign a lat long to the point
point = new OpenLayers.Geometry.Point(lat,lon);
Add point to vectors
vectors.addFeatures([new OpenLayers.Feature.Vector(point)]);
map.setCenter(center, 15);
//add vectors to map
map.addLayer(vectors);
}
Am I missing something?
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评论（2）
你在看完整地图吗？您很有可能将该点的位置设置为纬度/经度。 OpenLayers LonLat 对象如此命名只是为了欺骗像您这样的无辜用户，让他们认为它会自动转换纬度经度，或者期望它们，或者其他什么。不要相信它，重新投影到地图的投影中。
Are you looking at the full map? There's a high chance that you're setting the point's location as lat/lon. The OpenLayers LonLat object is so named only to trick innocent users like you into thinking that it automatically converts latitude longitude, or expects them, or something. Don't trust it, reproject into the projection of your map.
我认为收集是必要的，但看起来你有纬度和纬度隆交换了。一个点必须有 lon，然后有 lat。
I thought Collection were necessary, but looks like you have lat & lon swapped. A point must have lon, then lat.