在matlab中比较两个相同长度的不同向量

发布于 2024-12-17 22:44:58 字数 451 浏览 2 评论 0原文

我有两个矩阵 A 和 B。A 是一个长度为 1000X1 的数组，由 0 和 1 组成，B 也具有相同的大小。现在 B 是一个以 A 作为输入执行扫描操作的函数的输出。扫描只不过是在 A 中的 1 位置添加零。因此，B 的值与 A 类似，只是其中一些 1 被替换为 0。现在我的任务是填充 B 中的那些 0 值，这些值在扫描操作后被随机二进制值替换。我是在这个很棒的网站的用户的帮助下完成的。相同的代码在这里

idx=strfind(B,[0 0 0 0]);
n=dec2bin(randi([0 15],[numel(idx) 1]),4) - '0';
idx=bsxfun(@plus, idx', (0:3));
xx = B;
xx(idx(:)) = n(:);

现在这个函数还将替换 A 中已经存在的零。我只想替换那些从 1 更改为 0 的零，而不替换 A 中已经为零的那些 0。任何帮助我们将非常感激。

原文

I have two matrix A and B. A is a array of length 1000X1 consisting of 0's and 1's and B is also of the same size. Now B is the output of a function that performs a sweep operation taking A as input. Sweep is nothing but addition of zeros in the place of 1 in A. so values of B is similar to A except some of the 1's are replaced by 0's. Now my task is to fill those 0 values in B which was replaced after sweep operation by random binary values.I have done this with help of a user form this awesome website. And the code for the same is here

idx=strfind(B,[0 0 0 0]);
n=dec2bin(randi([0 15],[numel(idx) 1]),4) - '0';
idx=bsxfun(@plus, idx', (0:3));
xx = B;
xx(idx(:)) = n(:);

Now this function will also replace the zeros which was already present in A. I want to replace only those zeros which were changed from 1's to 0's and not those 0's which were already zeros in A. Any help would be very much appreciated.

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微暖i 2024-12-24 22:44:58

我会这样做：

function modifiedB=modifyB(A,B)
  idx=(A~=B); %% or idx=((A==1)&(B==0)); %% find the indices where B changed
  B(idx)=(rand(nnz(idx),1)>0.5); %% replace at those indices by random numbers
  modifiedB=B;
end

I would do:

function modifiedB=modifyB(A,B)
  idx=(A~=B); %% or idx=((A==1)&(B==0)); %% find the indices where B changed
  B(idx)=(rand(nnz(idx),1)>0.5); %% replace at those indices by random numbers
  modifiedB=B;
end

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