Android 版 gtalk 中的群聊

发布于 2024-12-17 10:03:45 字数 981 浏览 0 评论 0原文

我正在使用 smack 3.2.1 API 制作 gtalk。我陷入了群聊实施的困境。这是我发起群聊的代码：

conf = new MultiUserChat(connection, "[email protected]");  // create object of multiserchat class

         try 
         {  // Create the room
            conf.create("[email protected]");

            // Send an empty room configuration form which indicates that we want an instant room
            conf.sendConfigurationForm(new Form(Form.TYPE_SUBMIT));
         } 

         catch (XMPPException e) 
         {
            Toast.makeText(this, "Error in create room: "+e.toString(), Toast.LENGTH_LONG).show();
         }

conf.invite("userid", "Invitation for group chat");

但我收到错误：服务不可用（503）

提前致谢。

原文

I am making gtalk Im using smack 3.2.1 API.
I am stuck with group chat implementation.
here is my code for initiate a group chat:

conf = new MultiUserChat(connection, "[email protected]");  // create object of multiserchat class

         try 
         {  // Create the room
            conf.create("[email protected]");

            // Send an empty room configuration form which indicates that we want an instant room
            conf.sendConfigurationForm(new Form(Form.TYPE_SUBMIT));
         } 

         catch (XMPPException e) 
         {
            Toast.makeText(this, "Error in create room: "+e.toString(), Toast.LENGTH_LONG).show();
         }

conf.invite("userid", "Invitation for group chat");

But I am getting error: Service not Available (503)

Thanks in advance.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

枕头说它不想醒 2024-12-24 10:03:45

房间应该是——私人聊天——

并且不需要创建房间。

只需使用用户名和密码即可加入房间。这将满足：

代码片段：

String room = "private-chat-" + UUID.randomUUID().toString();
room = room + "@groupchat.google.com";
MultiUserChat muc = new MultiUserChat(cc, room);
    muc.join("username", "password");
    muc.invite("username", "hi");

让我知道这是否有效。

Room should be -- private-chat-

And there is no need to create room.

Simply join the room with users name and password. That will satishfy:

Code snippet:

String room = "private-chat-" + UUID.randomUUID().toString();
room = room + "@groupchat.google.com";
MultiUserChat muc = new MultiUserChat(cc, room);
    muc.join("username", "password");
    muc.invite("username", "hi");

Let me know if this works.

回复收藏 0 原文

~没有更多了~