如何从导航控制器一次弹出两个视图？

发布于 2024-12-17 08:23:38 字数 161 浏览 0 评论 0原文

我想将导航堆栈上的第三个视图弹回到第一个视图。

我知道如何一次弹出一个视图：

[self.navigationController popViewControllerAnimated:YES];

但是如何同时弹出两个视图呢？

原文

I want to pop to the third view on the navigation stack back to the first view.

I know how to pop one view at once:

[self.navigationController popViewControllerAnimated:YES];

But how do I do two at once?

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围归者 2024-12-24 08:23:38

您也可以尝试在导航控制器堆栈之间跳转

NSMutableArray *allViewControllers = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
for (UIViewController *aViewController in allViewControllers) {
    if ([aViewController isKindOfClass:[RequiredViewController class]]) {
        [self.navigationController popToViewController:aViewController animated:NO];
    }
}

You can try this to Jump between the navigation controller stack as well

NSMutableArray *allViewControllers = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
for (UIViewController *aViewController in allViewControllers) {
    if ([aViewController isKindOfClass:[RequiredViewController class]]) {
        [self.navigationController popToViewController:aViewController animated:NO];
    }
}

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翻了热茶 2024-12-24 08:23:38

这里有两个 UINavigationController 扩展可以解决您的问题。我建议使用第一个弹出到特定类的 UIViewController 的：

extension UINavigationController {

  func popToViewController(ofClass: AnyClass, animated: Bool = true) {
    if let vc = viewControllers.filter({$0.isKind(of: ofClass)}).last {
      popToViewController(vc, animated: animated)
    }
  }

  func popViewControllers(viewsToPop: Int, animated: Bool = true) {
    if viewControllers.count > viewsToPop {
      let vc = viewControllers[viewControllers.count - viewsToPop - 1]
      popToViewController(vc, animated: animated)
    }
  }

}

并像这样使用它：

// pop to SomeViewController class
navigationController?.popToViewController(ofClass: SomeViewController.self)

// pop 2 view controllers
navigationController?.popViewControllers(viewsToPop: 2)

Here are two UINavigationController extensions that can solve your problem. I would recommend using the first one that pops to a UIViewController of a specific class:

extension UINavigationController {

  func popToViewController(ofClass: AnyClass, animated: Bool = true) {
    if let vc = viewControllers.filter({$0.isKind(of: ofClass)}).last {
      popToViewController(vc, animated: animated)
    }
  }

  func popViewControllers(viewsToPop: Int, animated: Bool = true) {
    if viewControllers.count > viewsToPop {
      let vc = viewControllers[viewControllers.count - viewsToPop - 1]
      popToViewController(vc, animated: animated)
    }
  }

}

and use it like this:

// pop to SomeViewController class
navigationController?.popToViewController(ofClass: SomeViewController.self)

// pop 2 view controllers
navigationController?.popViewControllers(viewsToPop: 2)

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流绪微梦 2024-12-24 08:23:38

您可以使用 popToRootViewControllerAnimated 弹出到“根”（第一个）视图控制器：

[self.navigationController popToRootViewControllerAnimated:YES];

// If you want to know what view controllers were popd:
// NSArray *popdViewControllers = [self.navigationController popToRootViewControllerAnimated:YES];

UINavigationController 参考：

弹出堆栈上除根视图控制器之外的所有视图控制器并更新显示。
返回值
从堆栈中弹出的视图控制器数组。

You can pop to the "root" (first) view controller with popToRootViewControllerAnimated:

[self.navigationController popToRootViewControllerAnimated:YES];

// If you want to know what view controllers were popd:
// NSArray *popdViewControllers = [self.navigationController popToRootViewControllerAnimated:YES];

UINavigationController Reference:

Pops all the view controllers on the stack except the root view controller and updates the display.
Return Value
An array of view controllers that are popped from the stack.

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夜未央樱花落 2024-12-24 08:23:38

[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];

objectAtIndex：1 -->你可以传递你想要弹出的任何索引

[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];

objectAtIndex:1 --> you can pass whichever index you want to pop to

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錯遇了你 2024-12-24 08:23:38

Swift 2 - xCode 7.3

这可能是弹出 UIViewControllers 的一个非常有用的扩展：

extension UINavigationController {

    func popToViewControllerOfType(classForCoder: AnyClass) {
        for controller in viewControllers {
            if controller.classForCoder == classForCoder {
                popToViewController(controller, animated: true)
                break
            }
        }
    }

    func popViewControllers(controllersToPop: Int, animated: Bool) {
        if viewControllers.count > controllersToPop {
            popToViewController(viewControllers[viewControllers.count - (controllersToPop + 1)], animated: animated)
        } else {
            print("Trying to pop \(controllersToPop) view controllers but navigation controller contains only \(viewControllers.count) controllers in stack")
        }
    }
}

Swift 2 - xCode 7.3

This could be a very useful extension to pop UIViewControllers:

extension UINavigationController {

    func popToViewControllerOfType(classForCoder: AnyClass) {
        for controller in viewControllers {
            if controller.classForCoder == classForCoder {
                popToViewController(controller, animated: true)
                break
            }
        }
    }

    func popViewControllers(controllersToPop: Int, animated: Bool) {
        if viewControllers.count > controllersToPop {
            popToViewController(viewControllers[viewControllers.count - (controllersToPop + 1)], animated: animated)
        } else {
            print("Trying to pop \(controllersToPop) view controllers but navigation controller contains only \(viewControllers.count) controllers in stack")
        }
    }
}

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雪落纷纷 2024-12-24 08:23:38

如果您只想一次弹出 2 个，因为您的 rootViewController（方式）“更深”，那么 2 您可以考虑向 UIviewController 添加一个类别，例如：

UINavigationController+popTwice.h

#import <UIKit/UIKit.h>
@interface UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated;

@end

UINavigationController+popTwice.m

#import "UINavigationController+popTwice.h"

@implementation UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated{
    [self popViewControllerAnimated:NO];
    [self popViewControllerAnimated:animated];
}

@end

导入类别 #import “UINavigationController+popTwice.h” 在您的实现中的某个位置，并使用这行代码一次弹出 2 个控制器：

[self.navigationController popTwoViewControllersAnimated:YES];

这不是很好吗？ :)

If you just want to pop 2 at once because your rootViewController is (way) 'deeper' then 2 you could consider adding a category to UIviewController for example:

UINavigationController+popTwice.h

#import <UIKit/UIKit.h>
@interface UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated;

@end

UINavigationController+popTwice.m

#import "UINavigationController+popTwice.h"

@implementation UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated{
    [self popViewControllerAnimated:NO];
    [self popViewControllerAnimated:animated];
}

@end

Import the category #import "UINavigationController+popTwice.h" somewhere in your implementation and use this line of code to pop 2 controllers at once:

[self.navigationController popTwoViewControllersAnimated:YES];

isn't that great? :)

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黯然#的苍凉 2024-12-24 08:23:38

Swift 4：

func popViewControllerss(popViews: Int, animated: Bool = true) {
    if self.navigationController!.viewControllers.count > popViews
    {
        let vc = self.navigationController!.viewControllers[self.navigationController!.viewControllers.count - popViews - 1]
         self.navigationController?.popToViewController(vc, animated: animated)
    }
}

然后使用此方法

self.popViewControllerss(popViews: 2)

Swift 4 :

func popViewControllerss(popViews: Int, animated: Bool = true) {
    if self.navigationController!.viewControllers.count > popViews
    {
        let vc = self.navigationController!.viewControllers[self.navigationController!.viewControllers.count - popViews - 1]
         self.navigationController?.popToViewController(vc, animated: animated)
    }
}

Then Use This Method

self.popViewControllerss(popViews: 2)

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橪书 2024-12-24 08:23:38

您也可以尝试这个：-

[self.navigationController popToViewController:yourViewController animated:YES];

You can also try this one :-

[self.navigationController popToViewController:yourViewController animated:YES];

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静若繁花 2024-12-24 08:23:38

//viewIndex = 1;
//viewIndex = 2;
//viewIndex = 3;

// **[viewControllers objectAtIndex: *put here your viewindex number*]

NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:[viewControllers objectAtIndex:viewIndex] animated:NO];

//viewIndex = 1;
//viewIndex = 2;
//viewIndex = 3;

// **[viewControllers objectAtIndex: *put here your viewindex number*]

NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:[viewControllers objectAtIndex:viewIndex] animated:NO];

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简美 2024-12-24 08:23:38

    NSMutableArray *newStack = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
    [newStack removeLastObject];
    [newStack removeLastObject];
    [self.navigationController setViewControllers:newStack animated:YES];

    NSMutableArray *newStack = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
    [newStack removeLastObject];
    [newStack removeLastObject];
    [self.navigationController setViewControllers:newStack animated:YES];

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无声无音无过去 2024-12-24 08:23:38

在 Swift 3 中，
您可以从导航控制器中弹出一个、两个或多个视图控制器，例如

let viewControllers = self.navigationController!.viewControllers as [UIViewController]
    for aViewController:UIViewController in viewControllers {
        if aViewController.isKind(of: FromWhereYouWantToGoController.self) {
            _ = self.navigationController?.popToViewController(aViewController, animated: true)
        }
    }

此处 FromWhereYouWantToGoController 是目标控制器。希望有帮助。

In Swift 3,
you can pop one, two or more viewcontrollers from navigation controller like that

let viewControllers = self.navigationController!.viewControllers as [UIViewController]
    for aViewController:UIViewController in viewControllers {
        if aViewController.isKind(of: FromWhereYouWantToGoController.self) {
            _ = self.navigationController?.popToViewController(aViewController, animated: true)
        }
    }

Here FromWhereYouWantToGoController is destination controller. Hope it helps.

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空宴 2024-12-24 08:23:38

您可以传递初始视图控制器（您想要返回的视图控制器），然后在最后一个视图中调用此行：

[self.navigationController popToViewController:yourInitialViewController animated:YES];

L。

You can pass the initial view controller (the one you want to come back to) and then call this line in the last view:

[self.navigationController popToViewController:yourInitialViewController animated:YES];

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治碍 2024-12-24 08:23:38

我在这里没有看到这个答案。如果您只想弹出一些（不是一直到根），您可以迭代 self.navigationController.viewControllers 检查类类型，或者如果您有引用，请使用：

for (UIViewController *aViewController in self.navigationController.viewControllers) {
   if ([aViewController isKindOfClass:[SMThumbnailViewController class]]) {
      [self.navigationController popToViewController:aViewController animated:YES];
   }
}

I didn't see this answer in here. If you only want to pop a few (not all the way to the root), you can just iterate through self.navigationController.viewControllers checking for class types, or if you have a reference use that:

for (UIViewController *aViewController in self.navigationController.viewControllers) {
   if ([aViewController isKindOfClass:[SMThumbnailViewController class]]) {
      [self.navigationController popToViewController:aViewController animated:YES];
   }
}

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﹏雨一样淡蓝的深情 2024-12-24 08:23:38

您可以弹回到根视图控制器

[self.navigationController popToRootViewControllerAnimated:YES];

，或者，如果您要弹到的视图不是第一个视图，则需要在上一个视图的 viewWillAppear 中再次弹起

you can pop back to the root view controller

[self.navigationController popToRootViewControllerAnimated:YES];

or, if the view you want to pop to isn't the first one, you'll need to pop again in your previous view's viewWillAppear

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尘世孤行 2024-12-24 08:23:38

这是我用来返回 X ViewControllers 的一个小函数：

-(void)backMultiple:(id)data {
    int back = 2; //Default to go back 2 
    int count = [self.navigationController.viewControllers count];

    if(data[@"count"]) back = [data[@"count"] intValue];

    //If we want to go back more than those that actually exist, just go to the root
    if(back+1 > count) {
        [self.navigationController popToRootViewControllerAnimated:YES];
    }
    //Otherwise go back X ViewControllers 
    else {
        [self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:count-(back+1)] animated:YES];
    }
}

Here's a little function I'm using to go back X ViewControllers:

-(void)backMultiple:(id)data {
    int back = 2; //Default to go back 2 
    int count = [self.navigationController.viewControllers count];

    if(data[@"count"]) back = [data[@"count"] intValue];

    //If we want to go back more than those that actually exist, just go to the root
    if(back+1 > count) {
        [self.navigationController popToRootViewControllerAnimated:YES];
    }
    //Otherwise go back X ViewControllers 
    else {
        [self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:count-(back+1)] animated:YES];
    }
}

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往日 2024-12-24 08:23:38

Swift 版本（Swift 1.2 / Xcode 6.3.1）
弹出两次或更多次

 var viewControllers = self.navigationController?.viewControllers
 viewControllers?.removeLast()
 viewControllers?.removeLast()
 self.navigationController?.setViewControllers(viewControllers, animated: true)

或

 var viewControllers = self.navigationController?.viewControllers
 var viewsToPop = 2
 var end = (viewControllers?.count)!
 var start = end - viewsToPop
 viewControllers?.removeRange(Range<Int>(start: start, end: end))
 self.navigationController?.setViewControllers(viewControllers, animated: true)

Swift Version as of (Swift 1.2 / Xcode 6.3.1)
of popping twice or more

 var viewControllers = self.navigationController?.viewControllers
 viewControllers?.removeLast()
 viewControllers?.removeLast()
 self.navigationController?.setViewControllers(viewControllers, animated: true)

 var viewControllers = self.navigationController?.viewControllers
 var viewsToPop = 2
 var end = (viewControllers?.count)!
 var start = end - viewsToPop
 viewControllers?.removeRange(Range<Int>(start: start, end: end))
 self.navigationController?.setViewControllers(viewControllers, animated: true)

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厌倦 2024-12-24 08:23:38

您可以使用 UIViewController 的堆栈。
1. 获取堆栈中所有viewController 的数组。
2. 遍历整个数组并找到想要的viewController
通过匹配类类型。
3.弹出viewController。

func popToSpecificViewC
{
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
        for viewController:UIViewController in viewControllers
        {
            if viewController.isKind(of: WelcomeViewC.self)
            {
                _ = self.navigationController?.popToViewController(viewController, animated: true)
            }
        }
}

You can use the stack of the UIViewControllers.
1. Fetch the array of all the viewControllers in the stack.
2. Iterate through the whole array and find the desired viewController
by matching the class type.
3. Pop the viewController.

func popToSpecificViewC
{
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
        for viewController:UIViewController in viewControllers
        {
            if viewController.isKind(of: WelcomeViewC.self)
            {
                _ = self.navigationController?.popToViewController(viewController, animated: true)
            }
        }
}

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上课铃就是安魂曲 2024-12-24 08:23:38

使用简单的 UINavigationController 扩展：

extension UINavigationController {
    func popViewControllers(_ count: Int) {
        guard viewControllers.count > count else { return }
        popToViewController(viewControllers[viewControllers.count - count - 1], animated: true)
    }
}

Using a simple UINavigationController extension:

extension UINavigationController {
    func popViewControllers(_ count: Int) {
        guard viewControllers.count > count else { return }
        popToViewController(viewControllers[viewControllers.count - count - 1], animated: true)
    }
}

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