如何让 UITouch 返回 float 而不是 int ？
我正在根据 UITouch 分配视图的中心。我读到 UITouch 返回一个 int 值——这意味着它没有给我触摸的确切位置。有什么方法可以投射触摸值，以便我获得触摸点的不圆角位置？
CGPoint touchPoint = [touch locationInView:self];
self.thumb.center = CGPointMake(touchPoint.x, touchPoint.y);
I'm assigning the center of a view based on a UITouch. I read that UITouch returns an int value -- meaning that it doesn't give me the exact location of the touch. Is there any way to cast the touch value so that I get the unrounded location of the touchpoint?
CGPoint touchPoint = [touch locationInView:self];
self.thumb.center = CGPointMake(touchPoint.x, touchPoint.y);
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您到底在哪里读到 UITouch 返回 int 值？这完全是错误的。您的代码已经证明了它是多么错误，因为您已经知道 UITouch 返回一个 CGPoint 值。如果您查看
CGPoint的定义，它由两个CGFloat字段组成，因此它已经是一个浮点值。Where exactly did you read that a UITouch returns an int value? That's just plain wrong. Your code already demonstrates how wrong it is, since you already know that a UITouch returns a
CGPointvalue. If you look at the definition ofCGPoint, it's made up of twoCGFloatfields, so it's already a floating-point value.