如何对多列主键进行窗口查询？

Question

基于此处找到的示例，但我想我是不理解它。这适用于单列主键，但不适用于多个主键。 这是我的代码

@classmethod
    def column_windows(cls, q, columns, windowsize, where = None):
        """Return a series of WHERE clauses against 
        a given column that break it into windows.

        Result is an iterable of tuples, consisting of
        ((start, end), whereclause), where (start, end) are the ids.

        Requires a database that supports window functions, 
        i.e. Postgresql, SQL Server, Oracle.

        Enhance this yourself !  Add a "where" argument
        so that windows of just a subset of rows can
        be computed.
        """
             #Here is the thing... how to compare...
        def int_for_range(start_id, end_id):
            if end_id:
                return and_(
                    columns>=start_id,
                    columns<end_id
                )
            else:
                return columns>=start_id

        if isinstance(columns, Column):
            columns_k=(columns,)
        else:
            columns_k=tuple(columns)
        q2=None
        cols=()
        for c in columns:
            cols = cols + (c,)
            if not q2:
                q2=q.session.query(c)
            else:
                q2=q2.add_column(c)
        q2 = q2.add_column(func.row_number().over(order_by=columns_k).label('rownum'))
        q2=q2.filter(q._criterion).from_self(cols)
        if windowsize > 1:
            q2 = q2.filter("rownum %% %d=1" % windowsize)
        for res in q2:
            print res
        intervals = [id for id, in q2]
        while intervals:
            start = intervals.pop(0)
            if intervals:
                end = intervals[0]
            else:
                end = None
            yield int_for_range(start, end)

    @classmethod
    def windowed_query(cls, q, columns, windowsize):
        """"Break a Query into windows on a given column."""

        for whereclause in cls.column_windows(q,columns, windowsize):
            for row in q.filter(whereclause).order_by(columns):
                yield row

现在我在比较主键的列集时遇到问题。好吧，我想某种递归子句生成函数应该可以做到这一点......让我们尝试一下......

Answer 1

好吧，结果不是预期的结果，但让它工作了：现在它真的窗口任何查询保持所有就位，多列唯一排序，等等：
这是我的代码，希望对其他人有用：

@classmethod
    def window_query(cls, q, windowsize, windows=None):
        """
            q=Query object we want to window results
            windowsize=The number of elements each window has
            windows=The window, or window list, numbers: 1-based to query
        """
        windowselect=False
        if windows:
            if not isinstance(windows,list):
                windows=list(windows)
            windowselect=True
        #Appending u_columns to ordered counting subquery will ensure unique ordering
        u_columns=list([col for col in cls.getBestUniqueColumns()])
        #o_columns is the list of order by columns for the query
        o_columns=list([col for col in q._order_by])
        #we append columns from u_columns not in o_columns to ensure unique ordering but keeping the desired one
        sq_o_columns=list(o_columns)
        for col in u_columns:
            if not col in sq_o_columns:
                sq_o_columns.append(col)

        sub=None
        #we select unique columns in subquery that we'll need to join in parent query
        for col in u_columns:
            if not sub:
                sub=q.session.query(col)
            else:
                sub=sub.add_column(col)

        #Generate a tuple from sq_o_columns list (I don't know why over() won't accept list itself TODO: more elegant
        sq_o_col_tuple=()
        for col in sq_o_columns:
            sq_o_col_tuple=sq_o_col_tuple + (col,)
        #we add row counting column, counting on generated combined ordering+unique columns tuple
        sub = sub.add_column(func.row_number().over(order_by=sq_o_col_tuple).label('rownum')).filter(q._criterion)

        #Prepare sub query to use as subquery (LOL)
        sub=sub.subquery('lacrn')

        #Prepare join ON clauses epxression comparing unique columns defined by u_columns 
        joinclause=expression.BooleanClauseList()
        for col in u_columns:
            joinclause=joinclause.__and__(col == sub.c[col.key])
        #Make the joining
        q=q.join(sub,joinclause
                 )
        i=-1
        while True:
            #We try to query windows defined by windows list
            if windowselect:
                #We want selected-windows-results to returned
                if windows:
                    i=windows.pop(0)-1
                else:
                    break
            else:
                #We want all-windows-results to be returned
                i=i+1
            res=q.filter(and_(sub.c.rownum > (i*windowsize), sub.c.rownum <= ((i+1)*windowsize))).all()
            if not (res or windowselect):
                #We end an all-windows-results because of no more results, we must check if is selected-window-query
                #because of selected-window-results may not exist and the are unordered
                #EX: [1,2,9999999999999,3] : Assuming the third page required has no results it will return pages 1, 2, and 3 
                break
            for row in res:
                yield row