如何从 html select 中删除选定的选项？

发布于 2024-12-16 16:07:36 字数 3506 浏览 1 评论 0原文

与标题相比，我的实际问题相当复杂。我对 Javascript 和 jQuery 很陌生，所以请耐心等待。

我建议您在阅读我的问题之前先运行此代码，以便您可以理解我想要做什么。

<html>
<head>
<script type="text/javascript" src="jquery1.6.4min.js"></script>
<script type="text/javascript" > 
var selectedAddFootballPlayerId = '';
var selectedAddFootballPlayerName = '';
var selectedRemoveFootballPlayerId = '';
var selectedRemoveFootballPlayerName = '';

$(document).ready(function() {
 $('#listboxFootballPlayers option').click(function() {
  selectedAddFootballPlayerId = $(this).attr('value');
  selectedAddFootballPlayerName = $(this).text();
 });

 $('#selectedFootballPlayers option').click(function() {
  selectedRemoveFootballPlayerId = $(this).attr('value');
  selectedRemoveFootballPlayerName = $(this).text();
 });

 $('input#btnAddFootballPlayerToList').click(function() {
  if (selectedAddFootballPlayerId == '') {
   alert("Select a football player to be added from the list.");
  } else {
   var option = new Option(selectedAddFootballPlayerName , selectedAddFootballPlayerId);
   $(option).html(selectedAddFootballPlayerName); 
   $('#selectedFootballPlayers').append(option);
   selectedAddFootballPlayerId = '';
   selectedAddFootballPlayerName = '';
  }
 });

 $('input#btnRemoveFootballPlayerFromList').click(function() {
  if (selectedRemoveFootballPlayerId == '') {
   alert("Select a football player to be removed from the list.");
  } else {
   var option = new Option(selectedRemoveFootballPlayerName , selectedRemoveFootballPlayerId);
   $(option).html(selectedRemoveFootballPlayerName); 
   $('#listboxFootballPlayers').append(option);
   selectedRemoveFootballPlayerId = '';
   selectedRemoveFootballPlayerName = '';
  }
 });
});
</script>
</head>
<body>
<table>
 <tr>
  <td>
   <select id="listboxFootballPlayers" size="5" multiple="multiple" style="width: 200px;">
    <option value="l1">Cristiano Ronaldo</option>
    <option value="l2">Ricardo Kaka</option>
    <option value="l3">Lionel Messi</option>
    <option value="l4">Gerd Muller</option>
    <option value="l5">Johan Crujjf</option>
    <option value="l6">Franz Beckenbauer</option>
    <option value="l7">David Beckham</option>
   </select>
  </td>
                    
  <td>
   <table>
    <tr><td><input type="button" id="btnAddFootballPlayerToList" value="->" /> </td></tr>
    <tr><td><input type="button" id="btnRemoveFootballPlayerFromList" value="<-" /></td></tr>
   </table>
  </td>
                        
  <td>
   <select id="selectedFootballPlayers" size="5" multiple="multiple" style="width: 200px;"></select>
  </td>
 </tr>
 </table>
 </body>
 </html>

在开始提问之前，请注意：

#listboxFootballPlayers - 左侧的列表框
#selectedFootballPlayers - 右侧的列表框

我有 2 个问题：

单击 - 后如何从 #listboxFootballPlayers 中删除所选项目/选项> 按钮。
为什么当我从 #selectedFootballPlayers 选择一个项目/选项后单击 <- 时，它会给我一条消息选择一名足球运动员从列表中删除。在我看来，它没有为变量selectedRemoveFootballPlayerId分配值。

如果我的问题有什么不清楚的地方，请询问我。请帮忙。

这是 jsfiddle 链接： http://jsfiddle.net/7vspM/

原文

My actual question is quite bit complicated compared to its title. I am very new to Javascript and jQuery so please bear with me.

I would suggest that you run this code first before reading my question so you can understand what I'm trying to do.

<html>
<head>
<script type="text/javascript" src="jquery1.6.4min.js"></script>
<script type="text/javascript" > 
var selectedAddFootballPlayerId = '';
var selectedAddFootballPlayerName = '';
var selectedRemoveFootballPlayerId = '';
var selectedRemoveFootballPlayerName = '';

$(document).ready(function() {
 $('#listboxFootballPlayers option').click(function() {
  selectedAddFootballPlayerId = $(this).attr('value');
  selectedAddFootballPlayerName = $(this).text();
 });

 $('#selectedFootballPlayers option').click(function() {
  selectedRemoveFootballPlayerId = $(this).attr('value');
  selectedRemoveFootballPlayerName = $(this).text();
 });

 $('input#btnAddFootballPlayerToList').click(function() {
  if (selectedAddFootballPlayerId == '') {
   alert("Select a football player to be added from the list.");
  } else {
   var option = new Option(selectedAddFootballPlayerName , selectedAddFootballPlayerId);
   $(option).html(selectedAddFootballPlayerName); 
   $('#selectedFootballPlayers').append(option);
   selectedAddFootballPlayerId = '';
   selectedAddFootballPlayerName = '';
  }
 });

 $('input#btnRemoveFootballPlayerFromList').click(function() {
  if (selectedRemoveFootballPlayerId == '') {
   alert("Select a football player to be removed from the list.");
  } else {
   var option = new Option(selectedRemoveFootballPlayerName , selectedRemoveFootballPlayerId);
   $(option).html(selectedRemoveFootballPlayerName); 
   $('#listboxFootballPlayers').append(option);
   selectedRemoveFootballPlayerId = '';
   selectedRemoveFootballPlayerName = '';
  }
 });
});
</script>
</head>
<body>
<table>
 <tr>
  <td>
   <select id="listboxFootballPlayers" size="5" multiple="multiple" style="width: 200px;">
    <option value="l1">Cristiano Ronaldo</option>
    <option value="l2">Ricardo Kaka</option>
    <option value="l3">Lionel Messi</option>
    <option value="l4">Gerd Muller</option>
    <option value="l5">Johan Crujjf</option>
    <option value="l6">Franz Beckenbauer</option>
    <option value="l7">David Beckham</option>
   </select>
  </td>
                    
  <td>
   <table>
    <tr><td><input type="button" id="btnAddFootballPlayerToList" value="->" /> </td></tr>
    <tr><td><input type="button" id="btnRemoveFootballPlayerFromList" value="<-" /></td></tr>
   </table>
  </td>
                        
  <td>
   <select id="selectedFootballPlayers" size="5" multiple="multiple" style="width: 200px;"></select>
  </td>
 </tr>
 </table>
 </body>
 </html>

Before I start with the question please take note:

#listboxFootballPlayers - The listbox on the left
#selectedFootballPlayers - The listbox on the right

I have 2 questions:

How can I remove the selected item / option from #listboxFootballPlayers after I clicked on -> button.
Why is it that when I click on <- after I selected an item / option from #selectedFootballPlayers it gives me a message Select a football player to be removed from the list. It seems to me that it doesn't assign the value on the variable selectedRemoveFootballPlayerId.

Please ask me if there are something that are not clear with my question. Please help.

Here is the jsfiddle link: http://jsfiddle.net/7vspM/

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小情绪 2024-12-23 16:07:36

$(document).ready(function() {
    $('#listboxFootballPlayers option').click(function() {
        selectedAddFootballPlayerId = $(this).attr('value');
        selectedAddFootballPlayerName = $(this).text();
    });
    $('#selectedFootballPlayers option').live('click',  // `live()` event for `option` bcoz, option in this select will  
                                                        // create after DOM ready
    function() {
        selectedRemoveFootballPlayerId = $(this).attr('value');
        selectedRemoveFootballPlayerName = $(this).text();
    });
    $('input#btnAddFootballPlayerToList').click(function() {
        if (selectedAddFootballPlayerId == '') {
            alert("Select a football player to be added from the list.");
        } else {
            var option = new Option(selectedAddFootballPlayerName, selectedAddFootballPlayerId);
            $(option).html(selectedAddFootballPlayerName);
            $('#selectedFootballPlayers').append(option);
            $('#listboxFootballPlayers option:selected').remove();  // remove selected option
            selectedAddFootballPlayerId = '';
            selectedAddFootballPlayerName = '';
        }
    });
    $('input#btnRemoveFootballPlayerFromList').click(function() {
        if (selectedRemoveFootballPlayerId == '') {
            alert("Select a football player to be removed from the list.");
        } else {
            var option = new Option(selectedRemoveFootballPlayerName, selectedRemoveFootballPlayerId);
            $(option).html(selectedRemoveFootballPlayerName);
            $('#selectedFootballPlayers option:selected').remove(); // remove selected option
            $('#listboxFootballPlayers').append(option);
            selectedRemoveFootballPlayerId = '';
            selectedRemoveFootballPlayerName = '';
        }
    });
});

$(document).ready(function() {
    $('#listboxFootballPlayers option').click(function() {
        selectedAddFootballPlayerId = $(this).attr('value');
        selectedAddFootballPlayerName = $(this).text();
    });
    $('#selectedFootballPlayers option').live('click',  // `live()` event for `option` bcoz, option in this select will  
                                                        // create after DOM ready
    function() {
        selectedRemoveFootballPlayerId = $(this).attr('value');
        selectedRemoveFootballPlayerName = $(this).text();
    });
    $('input#btnAddFootballPlayerToList').click(function() {
        if (selectedAddFootballPlayerId == '') {
            alert("Select a football player to be added from the list.");
        } else {
            var option = new Option(selectedAddFootballPlayerName, selectedAddFootballPlayerId);
            $(option).html(selectedAddFootballPlayerName);
            $('#selectedFootballPlayers').append(option);
            $('#listboxFootballPlayers option:selected').remove();  // remove selected option
            selectedAddFootballPlayerId = '';
            selectedAddFootballPlayerName = '';
        }
    });
    $('input#btnRemoveFootballPlayerFromList').click(function() {
        if (selectedRemoveFootballPlayerId == '') {
            alert("Select a football player to be removed from the list.");
        } else {
            var option = new Option(selectedRemoveFootballPlayerName, selectedRemoveFootballPlayerId);
            $(option).html(selectedRemoveFootballPlayerName);
            $('#selectedFootballPlayers option:selected').remove(); // remove selected option
            $('#listboxFootballPlayers').append(option);
            selectedRemoveFootballPlayerId = '';
            selectedRemoveFootballPlayerName = '';
        }
    });
});

回复收藏 0 原文

涙—继续流 2024-12-23 16:07:36

关于 2)：

问题在于您在创建要分配的元素之前分配了单击功能。当您创建选项时，您应该分配它，如下所示：

$(option).click(function() {
 selectedRemoveFootballPlayerId = $(this).attr('value');
 selectedRemoveFootballPlayerName = $(this).text();
});

Regarding 2):

The problem is that you assign the click functionality before you create the element to assign it to. When you create your option you should assign it instead, like this:

$(option).click(function() {
 selectedRemoveFootballPlayerId = $(this).attr('value');
 selectedRemoveFootballPlayerName = $(this).text();
});

回复收藏 0 原文

够钟 2024-12-23 16:07:36

关于问题一，只需将选定的选项元素从一个列表移动到另一个列表会更容易一些：

$('#listboxFootballPlayers option:selected').appendTo('#selectedFootballPlayers');

我已注释掉 JS Fiddle 演示。

至于你的第二个问题，我重写了 if/else 语句：

$('input#btnRemoveFootballPlayerFromList').click(function() {
    if (!$('#selectedFootballPlayers option:selected')){
        alert("First select a player to remove.");
    }
    else {
        $('#selectedFootballPlayers option:selected').appendTo('#listboxFootballPlayers ');
    }
});

JS Fiddle 演示。

参考文献：

:selected。
appendTo()。

Regarding question one, it's somewhat easier to simply move the selected option element from one list to the other:

$('#listboxFootballPlayers option:selected').appendTo('#selectedFootballPlayers');

I've commented out the lines that don't appear to be needed in the JS Fiddle demo.

As for your second question, I've rewritten the if/else statement:

$('input#btnRemoveFootballPlayerFromList').click(function() {
    if (!$('#selectedFootballPlayers option:selected')){
        alert("First select a player to remove.");
    }
    else {
        $('#selectedFootballPlayers option:selected').appendTo('#listboxFootballPlayers ');
    }
});

JS Fiddle demo.

References:

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