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Matlab矩阵划分

发布于 2024-12-15 23:57:30 字数 85 浏览 6 评论 0原文

我想按近似均匀的行数来划分矩阵。例如，如果我有一个尺寸为 155 x 1000 的矩阵，如何将其除以 10，其中每个新矩阵的尺寸近似为 15 X 1000？

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围归者 2024-12-22 23:57:30

这个怎么样：

inMatrix = rand(155, 1000);
numRows  = size(inMatrix, 1);
numParts = 10;

a = floor(numRows/numParts);          % = 15
b = rem(numRows, numParts);           % = 5
partition = ones(1, numParts)*a;      % = [15 15 15 15 15 15 15 15 15 15]
partition(1:b) = partition(1:b)+1;    % = [16 16 16 16 16 15 15 15 15 15]
disp(sum(partition))                  % = 155

% Split matrix rows into partition, storing result in a cell array
outMatrices = mat2cell(inMatrix, partition, 1000)

outMatrices = 
[16x1000 double]
[16x1000 double]
[16x1000 double]
[16x1000 double]
[16x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]

How about this:

inMatrix = rand(155, 1000);
numRows  = size(inMatrix, 1);
numParts = 10;

a = floor(numRows/numParts);          % = 15
b = rem(numRows, numParts);           % = 5
partition = ones(1, numParts)*a;      % = [15 15 15 15 15 15 15 15 15 15]
partition(1:b) = partition(1:b)+1;    % = [16 16 16 16 16 15 15 15 15 15]
disp(sum(partition))                  % = 155

% Split matrix rows into partition, storing result in a cell array
outMatrices = mat2cell(inMatrix, partition, 1000)

outMatrices = 
[16x1000 double]
[16x1000 double]
[16x1000 double]
[16x1000 double]
[16x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]
[15x1000 double]

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不必你懂 2024-12-22 23:57:30

这是你想要的吗？

%Setup
x = rand(155,4);  %4 columns prints on my screen, the second dimension can be any size
n = size(x,1);
step = round(n/15);

%Now loop through the array, creating partitions
%    This loop just displays the partition plus a divider
for ixStart = 1:step:n
    part = x(  ixStart:(min(ixStart+step,end))  ,  :  );
    disp(part);
    disp('---------')
end

这里唯一的技巧是在下标的函数求值中使用 end 关键字。如果不使用关键字，您可以使用 size(x,1)，但这有点难以阅读。

Is this what you want?

%Setup
x = rand(155,4);  %4 columns prints on my screen, the second dimension can be any size
n = size(x,1);
step = round(n/15);

%Now loop through the array, creating partitions
%    This loop just displays the partition plus a divider
for ixStart = 1:step:n
    part = x(  ixStart:(min(ixStart+step,end))  ,  :  );
    disp(part);
    disp('---------')
end

The only trick here is the use of the end keyword within a function evaluation in the subscripting. Without using the keyword you could use size(x,1), but that is a bit harder to read.

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