创建/初始化共享内存中的对象（由mmap()打开）
我创建了共享内存并使用以下代码映射了我的对象：
shmfd = shm_open(SHMOBJ_PATH, O_CREAT | O_EXCL | O_RDWR, S_IRWXU | S_IRWXG);
ftruncate(shmfd, shared_seg_size);
bbuffer = (boundedBuffer *)mmap(NULL, shared_seg_size, PROT_READ | PROT_WRITE, MAP_SHARED, shmfd, 0);
现在我需要初始化并向 bbuffer 添加项目或从 bbuffer 中删除项目。当我尝试添加/删除时，出现“分段错误：11”，这表明程序访问了未分配的内存位置。我可以做什么来解决这个问题？
I created my shared memory and mapped my object with following code:
shmfd = shm_open(SHMOBJ_PATH, O_CREAT | O_EXCL | O_RDWR, S_IRWXU | S_IRWXG);
ftruncate(shmfd, shared_seg_size);
bbuffer = (boundedBuffer *)mmap(NULL, shared_seg_size, PROT_READ | PROT_WRITE, MAP_SHARED, shmfd, 0);
Now I need to initialize and add/remove items to/from bbuffer. When I try to add/remove, I get Segmentation Fault: 11, which indicates the program accessed a memory location that was not assigned. What can I do to solve this problem?
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一个疯狂的猜测：
void*和 32 位位int可能发生的情况是，编译器默认将
mmap作为返回int的值，将其转换为指针，从而与更高层的指针发生冲突。顺序位。切勿对
malloc或mmap等函数的返回值进行强制转换，并始终认真对待编译器的警告。A wild guess:
mmapincludedvoid*and 32 bitintWhat could happen there is that the compiler takes
mmapas returningintby default, casts this into a pointer and by that clashes the higher order bits.Never cast return values from functions such as
mallocormmap, and always take the warnings of your compiler seriously.