如何比较两个日期时间字符串并返回小时数差异？（bash外壳）

发布于 2024-12-15 07:44:10 字数 324 浏览 0 评论 0原文

我可以使用以下代码在 php 中执行此操作：

$dt1 = '2011-11-11 11:11:11';
$t1 = strtotime($dt1);

$dt2 = date('Y-m-d H:00:00');
$t2 = strtotime($dt2);

$tDiff = $t2 - $t1;

$hDiff = round($tDiff/3600);

$hDiff 将在几小时内给出结果。

如何在 bash shell 中实现上述内容？

原文

I can do that in php with the following code:

$dt1 = '2011-11-11 11:11:11';
$t1 = strtotime($dt1);

$dt2 = date('Y-m-d H:00:00');
$t2 = strtotime($dt2);

$tDiff = $t2 - $t1;

$hDiff = round($tDiff/3600);

$hDiff will give me the result in hours.

How do I implement the above in bash shell?

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淡写薰衣草的香 2024-12-22 07:44:10

您可以使用date命令来实现这一点。 man date 将为您提供更多详细信息。 bash 脚本可能是这样的（似乎在 Ubuntu 10.04 bash 4.1.5 上工作正常）：

#!/bin/bash                                                                                                                                                   

# Date 1
dt1="2011-11-11 11:11:11"
# Compute the seconds since epoch for date 1
t1=$(date --date="$dt1" +%s)

# Date 2 : Current date
dt2=$(date +%Y-%m-%d\ %H:%M:%S)
# Compute the seconds since epoch for date 2
t2=$(date --date="$dt2" +%s)

# Compute the difference in dates in seconds
let "tDiff=$t2-$t1"
# Compute the approximate hour difference
let "hDiff=$tDiff/3600"

echo "Approx hour diff b/w $dt1 & $dt2 = $hDiff"

希望这会有所帮助！

You could use date command to achieve this. man date will provide you with more details. A bash script could be something on these lines (seems to work fine on Ubuntu 10.04 bash 4.1.5):

#!/bin/bash                                                                                                                                                   

# Date 1
dt1="2011-11-11 11:11:11"
# Compute the seconds since epoch for date 1
t1=$(date --date="$dt1" +%s)

# Date 2 : Current date
dt2=$(date +%Y-%m-%d\ %H:%M:%S)
# Compute the seconds since epoch for date 2
t2=$(date --date="$dt2" +%s)

# Compute the difference in dates in seconds
let "tDiff=$t2-$t1"
# Compute the approximate hour difference
let "hDiff=$tDiff/3600"

echo "Approx hour diff b/w $dt1 & $dt2 = $hDiff"

Hope this helps!

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