如何在不指定标签名称的情况下读取 XML 中的子节点名称及其值？

发布于 2024-12-15 07:26:45 字数 1045 浏览 1 评论 0原文

在这里，我想循环遍历元素。虽然我可以在代码中指定标记名称，但我无法使用子级的标记名称。我想知道这些元素的标签名称及其值。

我怎样才能循环它们并做到这一点？

<?xml version="1.0" encoding="utf-8" ?>
<body>
  <detail>
    <FirstName>t1 </FirstName>
    <LastName>t2</LastName>
    <Company>t3</Company>
    <Country>t4</Country>
    <Proviance>MP</Proviance>
    <city>indore</city>
  </detail>

  <detail>
    <FirstName>t5 </FirstName>
    <LastName>t6</LastName>
    <Company>t7</Company>
    <Country>t8</Country>
    <Proviance>t9</Proviance>
  </detail>

  <detail>
    <FirstName>t10 </FirstName>
    <LastName>t11</LastName>
    <Company>t12</Company>
    <Country>t13</Country>
    <Proviance>t14</Proviance>
  </detail>

</body>

原文

Here, I want to loop through the <detail> elements. Although I can specify the <detail> tag name in my code, I can't use the tag names of the children. I want to know the tag names of those elements and their values.

How can I loop through them and do this?

<?xml version="1.0" encoding="utf-8" ?>
<body>
  <detail>
    <FirstName>t1 </FirstName>
    <LastName>t2</LastName>
    <Company>t3</Company>
    <Country>t4</Country>
    <Proviance>MP</Proviance>
    <city>indore</city>
  </detail>

  <detail>
    <FirstName>t5 </FirstName>
    <LastName>t6</LastName>
    <Company>t7</Company>
    <Country>t8</Country>
    <Proviance>t9</Proviance>
  </detail>

  <detail>
    <FirstName>t10 </FirstName>
    <LastName>t11</LastName>
    <Company>t12</Company>
    <Country>t13</Country>
    <Proviance>t14</Proviance>
  </detail>

</body>

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东走西顾 2024-12-22 07:26:45

怎么样；

var details = xml.getElementsByTagName("detail");

for (var i = 0; i < details.length; i++) {
    if (details[i].childNodes) {
        for (var j = 0; j < details[i].childNodes.length; j++) {
            var detail = details[i].childNodes[j];
            if (detail.nodeType === 1)
                alert( "details node " + (i + 1) + ": " + detail.nodeName + "=" + detail.firstChild.nodeValue );
        }
    }
}

How about;

var details = xml.getElementsByTagName("detail");

for (var i = 0; i < details.length; i++) {
    if (details[i].childNodes) {
        for (var j = 0; j < details[i].childNodes.length; j++) {
            var detail = details[i].childNodes[j];
            if (detail.nodeType === 1)
                alert( "details node " + (i + 1) + ": " + detail.nodeName + "=" + detail.firstChild.nodeValue );
        }
    }
}

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