C：主函数中的argv声明
您认为哪种方式在 main 函数中声明 argv 参数更好？为什么？
int main(int argc, char **argv /* char *argv[] */ /* char (*argv)[] */) {
//...
}
argv 最终作为指针进入函数 - 只是作为 argv 地址的副本，但不是作为数组，对吗？所以我认为，其他选择在语法上也必须是正确的，但你更喜欢哪种方式？
问候
What do you think which way is better declaring the argv argument in the main function and why?
int main(int argc, char **argv /* char *argv[] */ /* char (*argv)[] */) {
//...
}
argv comes into the function ultimately as a pointer - just as a copy of the argv address, but not as an array, right? So I think, the other alternatives must also be syntactically correct, but which way would you prefer?
Regards
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评论（4）
char *argv[]的含义最为明确——字符串数组。如果你很懒的话，
char **argv是最快的输入方式。char (*argv)[]我不确定你为什么要使用。char *argv[]is most explicit as to what it means -- an array of strings.char **argvis fastest to type if you're lazy.char (*argv)[]I'm not sure why you'd use.使用
*argv[]是传统方式，但我也见过使用**argv的程序。变体
(*argv)[]实际上与*argv[]相反，第一个是指向数组的指针（在本例中这是错误的），最后是一个指针数组。Using
*argv[]is the traditional way, but I have seen programs using**argvas well.The variant
(*argv)[]is actually the opposite of*argv[], the first is a pointer to an array (which is wrong in this case), the last is an array of pointers.我个人更喜欢
，因为它更好地描述了 argv，IMO。它是一个
char*数组，即一个字符串数组，这正是我所期望的argv。不是双指针。第三种变体看起来不错，与第二种相同。I personally prefer
because it describes
argvbetter, IMO. It's an array ofchar*, that is an array of strings, which is what I expectargvto be. Not a double pointer. The third variant seems ok and is equivalent to the second one.我喜欢 char *argv[] ，因为它是实际传递内容的最清晰表达；指向字符串的指针数组。
char **argv更简洁，但我觉得“指向指针的指针”并不能准确描述正在传递的内容。第三个选项中额外的括号只会让事情变得混乱。
I like
char *argv[]as it is the clearest expression of what is actually passed; an array of pointers to character strings.char **argvis more consise but I feel "pointer to pointer" does not accuratly describe wahts being passed.The extra parenthesis in the third option just confuse things.