另存为提示“图像名称”在通用 handler.ashx 中？

Question

当我使用 Handler.ashx ans 显示文件夹中的图像时，然后尝试通过右键单击图像来保存图像，它会不断向我提供“另存为类型”asp.net 通用处理程序选项，并将处理程序名称作为文件名

Bitmap target = new Bitmap(width, height);
    using (Graphics graphics = Graphics.FromImage(target)) {
        graphics.CompositingQuality = CompositingQuality.HighSpeed;
        graphics.InterpolationMode = InterpolationMode.HighQualityBicubic;
        graphics.CompositingMode = CompositingMode.SourceCopy;
        graphics.DrawImage(photo, 0, 0, width, height);
        using (MemoryStream memoryStream = new MemoryStream()) {
            target.Save(memoryStream, ImageFormat.Png);
            OutputCacheResponse(context, File.GetLastWriteTime(photoPath));
            using (FileStream diskCacheStream = new FileStream(cachePath, FileMode.CreateNew))
            {
                memoryStream.WriteTo(diskCacheStream);
            }
            memoryStream.WriteTo(context.Response.OutputStream);
        }
    }

。是处理程序，

ImageTiff.ImageUrl = "Handler.ashx?p=" + Parameter; 

这是后面的代码。

我需要使用图像名称而不是 handler.ashx 保存它

Answer 1

您应该在发送数据之前设置 ContentType 和 Content-Disposition HTTP 标头：

context.Response.ContentType = "image/png";
context.Response.Headers["Content-Disposition"] = "attachment; filename=yourfilename.png";

Answer 2

          context.Response.ContentType = "image/pjpeg"; 
          context.Response.AddHeader("Content-Disposition", "attachment; filename=\"" + photoName  + "\"");

          OutputCacheResponse(context, File.GetLastWriteTime(photoPath));

           context.Response.Flush();


           using (FileStream diskCacheStream = new FileStream(cachePath, FileMode.CreateNew))
           {
               memoryStream.WriteTo(diskCacheStream);
           }
            memoryStream.WriteTo(context.Response.OutputStream);

睡个好觉，我猜你的帮助成功了:) 谢谢大家！

Answer 3

当您希望用户保存文件时，您需要发送“application/octet-stream”的ContentType。

这是我们使用的代码（在 vb.net 中，抱歉）（我刚刚验证了当 ashx 请求时，这确实为用户提供了正确的文件名）：

    With context
        Try
            ' Remove what other controls may have been put on the page
            .ClearContent()
            ' Clear any headers
            .ClearHeaders()
        Catch theException As System.Web.HttpException
            ' Ignore this exception, which could occur if there were no HTTP headers in the response
        End Try

        .ContentType = "application/octet-stream"
        .AddHeader("Content-Disposition", "attachment; filename=" & sFileNameForUser)

        .TransmitFile(sFileName)

        ' Ensure the file is properly flushed to the user
        .Flush()

        ' Ensure the response is closed
        .Close()

        Try
            .End()
        Catch
        End Try

    End With

C# 翻译：

try
{
        // Remove what other controls may have been put on the page
    context.ClearContent();
        // Clear any headers
    context.ClearHeaders();
}
catch (System.Web.HttpException theException)
{
        // Ignore this exception, which could occur if there were no HTTP headers in the response
}

context.ContentType = "application/octet-stream";
context.AddHeader("Content-Disposition", "attachment; filename=" + sFileNameForUser);

context.TransmitFile(sFileName);

    // Ensure the file is properly flushed to the user
context.Flush();

    // Ensure the response is closed
context.Close();

try
{
    context.End();
}
catch
{
}