如何对字符串进行 URL 编码
我有一个带有空格和 & 字符的 URL 字符串 (NSString)。如何对整个字符串（包括 & ＆ 符号和空格）进行 url 编码？
I have a URL string (NSString) with spaces and & characters. How do I url encode the entire string (including the & ampersand character and spaces)?
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对于使用 UTF8Encode 将 NSString 编码为 cString 的 php 函数 urlencode，如 [NSString UTF8String] 不起作用。
这是我的自定义目标 c NSString+ASCIIencode 类别，适用于所有 ASCII 值 0..255
标头
实现
For the php function urlencode encoding a NSString to a cString with UTF8Encode, like [NSString UTF8String] was not working.
Here is my custom objective c NSString+ASCIIencode Category with works with all ASCII values 0..255
Header
Implementation
我遇到了类似的问题，将复杂的字符串作为 POST 参数传递。我的字符串可以包含亚洲字符、空格、引号和各种特殊字符。我最终找到的解决方案是将我的字符串转换为匹配的unicode系列，例如“Hu0040Hu0020Hu03f5....”，使用[NSString stringWithFormat:@"Hu%04x",[string characterAtIndex:i]]从每个字符串中获取Unicode原始字符串中的字符。在 Java 中也可以完成同样的操作。
该字符串可以作为 POST 参数安全地传递。
在服务器端（PHP），我将所有“H”更改为“\”，并将结果字符串传递给 json_decode。最后一步是在将字符串存储到 MySQL 之前转义单引号。
这样我就可以在我的服务器上存储任何 UTF8 字符串。
I faced a similar problem passing complex strings as a POST parameter. My strings can contain Asian characters, spaces, quotes and all sorts of special characters. The solution I eventually found was to convert my string into the matching series of unicodes, e.g. "Hu0040Hu0020Hu03f5...." using [NSString stringWithFormat:@"Hu%04x",[string characterAtIndex:i]] to get the Unicode from each character in the original string. The same can be done in Java.
This string can be safely passed as a POST parameter.
On the server side (PHP), I change all the "H" to "\" and I pass the resulting string to json_decode. Final step is to escape single quotes before storing the string into MySQL.
This way I can store any UTF8 string on my server.
这个对我有用。
我从此链接找到了上述函数： http://useyourloaf .com/blog/how-to-percent-encode-a-url-string/
您还可以通过 swift 扩展使用此函数。如果有任何问题，请告诉我。
This one is working for me.
I found the above function from this link: http://useyourloaf.com/blog/how-to-percent-encode-a-url-string/
You can also use this function with swift extension. Please let me know if there is any issue.
//这是未经测试的
//This is without test
对于个别www表单编码的查询参数，我在NSString上做了一个类别：
For individual www form-encoded query parameters, I made a category on NSString:
根据以下博客
according to the following blog
这么多答案但对我不起作用，所以我尝试了以下内容：
希望它会对某人有所帮助。谢谢
So many answers but didn't work for me, so I tried the following:
Hopefully it'll help someone. thanks
在 Swift 3 中，请尝试以下操作：
由于
stringByAddingPercentEscapesUsingEncoding对非 URL 字符进行编码，但保留保留字符（例如!*'();:@& =+$,/?%#[]), 您可以像下面的代码一样对 url 进行编码：In Swift 3, please try out below:
Since,
stringByAddingPercentEscapesUsingEncodingencodes non URL characters but leaves the reserved characters (like!*'();:@&=+$,/?%#[]), You can encode the url like the following code:在我的例子中，最后一个组件是阿拉伯字母，我在 Swift 2.2 中执行了以下操作：
用法：
In my case where the last component was Arabic letters I did the following in
Swift 2.2:usage:
在快速3中：
In swift 3:
基于 chown 在此线程中的 objc 答案的 swift 代码。
swift code based on chown's objc answer in this thread.
使用 NSURLComponents 对 HTTP GET 参数进行编码：
http://www.ralfebert。 de/snippets/ios/encoding-nsurl-get-parameters/
Use NSURLComponents to encode HTTP GET parameters:
http://www.ralfebert.de/snippets/ios/encoding-nsurl-get-parameters/
Apple 在 10.11 发行说明中的建议是：
如果需要对整个 URL 字符串进行百分比编码，则可以使用此代码对旨在成为 URL 的 NSString 进行编码（在 urlStringToEncode 中）：
Apple's advice, in the 10.11 release notes, is:
If you need to percent-encode an entire URL string, you can use this code to encode a NSString intended to be a URL (in urlStringToEncode):
在阅读了该主题的所有答案以及（错误）已接受的答案后，我想添加我的贡献。
如果目标是 iOS7+，并且在 2017 年应该会实现，因为 XCode 很难在 iOS8 下提供兼容性，最好的方法，线程安全，快速，AMD 将完全支持 UTF-8 来做到这一点是：
（目标 C 代码）
这将扩展 NSString，排除 RFC 禁止字符，支持 UTF-8 字符，并让您使用以下内容：
这将在调试控制台上打印：
... 注意还使用dispatch_once来避免多线程环境中的多次初始化。
After reading all the answers for this topic and the (wrong) accepted one, I want to add my contribution.
IF the target is iOS7+, and in 2017 it should since XCode makes really hard to deliver compatibility under iOS8, the best way, thread safe, fast, amd will full UTF-8 support to do this is:
(Objective C code)
This will extend NSString, will exclude RFC forbidden characters, support UTF-8 characters, and let you use things like:
That will print on your debug console:
... note also the use of dispatch_once to avoid multiple initializations in multithread environments.
这段代码帮助我编码特殊字符
This code helped me for encoding special characters
尝试将
stringByAddingPercentEncodingWithAllowedCharacters方法与[NSCharacterSet URLUserAllowedCharacterSet]一起使用，它将涵盖所有情况Objective C
swift
输出
测试%20%2F%20TestTry to use
stringByAddingPercentEncodingWithAllowedCharactersmethod with[NSCharacterSet URLUserAllowedCharacterSet]it will cover all the casesObjective C
swift
Output
Test%20%2F%20Test我选择使用接受的答案中给出的 CFURLCreateStringByAddingPercentEscapes 调用，但是在最新版本的 XCode（和 IOS）中，它导致了错误，因此使用了以下内容：
I opted to use the
CFURLCreateStringByAddingPercentEscapescall as given by accepted answer, however in newest version of XCode (and IOS), it resulted in an error, so used the following instead:以下是 Swift 5.x 中的生产就绪灵活方法：
示例用法：
输出：
Here's a production-ready flexible approach in Swift 5.x:
Example usage:
Output:
iOS 7 更新
ios 7 update
Swift 2.0 示例（兼容 iOS 9）
Swift 2.0 Example (iOS 9 Compatiable)
这可能对 iOS 7+ 有帮助
，推荐的方法是：
您可以根据 URL 组件的要求选择允许的字符集。
This might be helpful
For iOS 7+, the recommended way is:
You can choose the allowed character set as per the requirement of the URL component.
自选择答案后已添加新的 API；您现在可以使用 NSURLUtilities。由于 URL 的不同部分允许使用不同的字符，因此请使用适用的字符集。以下示例进行编码以包含在查询字符串中：
要专门转换“&”，您需要将其从 url 查询集中删除或使用不同的集合，如“&”在 URL 查询中允许：
New APIs have been added since the answer was selected; You can now use NSURLUtilities. Since different parts of URLs allow different characters, use the applicable character set. The following example encodes for inclusion in the query string:
To specifically convert '&', you'll need to remove it from the url query set or use a different set, as '&' is allowed in a URL query:
不幸的是，
stringByAddingPercentEscapesUsingEncoding并不总是 100% 有效。它对非 URL 字符进行编码，但保留保留字符（例如斜杠/和与号&）。显然这是苹果公司意识到的一个错误，但由于他们还没有修复它，我一直在使用这个类别来对字符串进行 url 编码：像这样使用：
这也有效：
一些好阅读有关该主题的内容：
Objective-c iPhone 百分比编码字符串？
Objective-C 和 Swift URL 编码
http://cybersam.com/programming/proper-url-percent-encoding-in-ios
https://devforums.apple.com/message/15674#15674
http://simonwoodside.com/weblog/2009/4/22/how_to_really_url_encode/
Unfortunately,
stringByAddingPercentEscapesUsingEncodingdoesn't always work 100%. It encodes non-URL characters but leaves the reserved characters (like slash/and ampersand&) alone. Apparently this is a bug that Apple is aware of, but since they have not fixed it yet, I have been using this category to url-encode a string:Used like this:
This also works:
Some good reading about the subject:
Objective-c iPhone percent encode a string?
Objective-C and Swift URL encoding
http://cybersam.com/programming/proper-url-percent-encoding-in-ios
https://devforums.apple.com/message/15674#15674
http://simonwoodside.com/weblog/2009/4/22/how_to_really_url_encode/