如何通过IInterceptionBehavior吞掉异常？

发布于 2024-12-14 05:45:00 字数 886 浏览 1 评论 0原文

我有一个像blow这样的IInterceptionBehavior：

public class TraceBehavior : IInterceptionBehavior
{
    public IEnumerable<Type> GetRequiredInterfaces()
    {
        return Type.EmptyTypes;
    }

    public IMethodReturn Invoke(IMethodInvocation input, GetNextInterceptionBehaviorDelegate getNext)
    {
        Console.WriteLine(string.Format("Invoke method:{0}",input.MethodBase.ToString()));
        IMethodReturn result = getNext()(input, getNext);
        if (result.Exception == null)
        {
            Console.WriteLine("Invoke successful!");
        }
        else 
        {
            Console.WriteLine(string.Format("Invoke faild, error: {0}", result.Exception.Message));
            result.Exception = null;
        }
        return result;
    }

    public bool WillExecute { get { return true; } }
}

无论我是否将其放在方法上，异常总是抛出。有人可以帮助我吗？

原文

I have a IInterceptionBehavior like blow:

public class TraceBehavior : IInterceptionBehavior
{
    public IEnumerable<Type> GetRequiredInterfaces()
    {
        return Type.EmptyTypes;
    }

    public IMethodReturn Invoke(IMethodInvocation input, GetNextInterceptionBehaviorDelegate getNext)
    {
        Console.WriteLine(string.Format("Invoke method:{0}",input.MethodBase.ToString()));
        IMethodReturn result = getNext()(input, getNext);
        if (result.Exception == null)
        {
            Console.WriteLine("Invoke successful!");
        }
        else 
        {
            Console.WriteLine(string.Format("Invoke faild, error: {0}", result.Exception.Message));
            result.Exception = null;
        }
        return result;
    }

    public bool WillExecute { get { return true; } }
}

Regardless of whether I put it upon methods or not, exception throw always. Anyone can help me?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

苏璃陌 2024-12-21 05:45:00

代码看起来不错，但您没有显示如何注册拦截以及如何调用对象。

假设正在调用拦截，那么如果我猜测调用的方法会返回值类型，并且 IMethodReturn.ReturnValue 为 null，这会导致 NullReferenceException。

如果是这种情况，那么返回值类型的默认值也许可以解决您的问题：

public IMethodReturn Invoke(IMethodInvocation input, GetNextInterceptionBehaviorDelegate getNext)
{
    Console.WriteLine(string.Format("Invoke method:{0}", input.MethodBase.ToString()));
    IMethodReturn result = getNext()(input, getNext);
    if (result.Exception == null)
    {
        Console.WriteLine("Invoke successful!");
    }
    else
    {
        Console.WriteLine(string.Format("Invoke faild, error: {0}", result.Exception.Message));
        result.Exception = null;

        Type type = ((MethodInfo)input.MethodBase).ReturnType;

        if (type.IsValueType)
        {
            result.ReturnValue = Activator.CreateInstance(type);
        }
    }
    return result;
}

The code looks OK but you haven't shown how the interception is registered and how the object is being called.

Assuming that interception is being called then if I were to guess it would be that that the method invoked returns a value type and IMethodReturn.ReturnValue is null which is causing a NullReferenceException.

If that is the case then perhaps returning the default value for a value type would solve your issue:

public IMethodReturn Invoke(IMethodInvocation input, GetNextInterceptionBehaviorDelegate getNext)
{
    Console.WriteLine(string.Format("Invoke method:{0}", input.MethodBase.ToString()));
    IMethodReturn result = getNext()(input, getNext);
    if (result.Exception == null)
    {
        Console.WriteLine("Invoke successful!");
    }
    else
    {
        Console.WriteLine(string.Format("Invoke faild, error: {0}", result.Exception.Message));
        result.Exception = null;

        Type type = ((MethodInfo)input.MethodBase).ReturnType;

        if (type.IsValueType)
        {
            result.ReturnValue = Activator.CreateInstance(type);
        }
    }
    return result;
}

回复收藏 0 原文

~没有更多了~