除非我移动光标,否则 SendInput 不会执行单击鼠标按钮的操作
除非我移动光标,否则 SendInput 不会执行单击鼠标按钮的操作。
我希望能在这方面得到帮助,因为我似乎无法理解它。
我有一个在前台窗口上执行鼠标单击的程序,其中我使用 SendInput 来模拟鼠标左键单击。 问题是,如果我将光标移动到单击位置,则 SendInput 将进行单击,但是如果我不移动光标,则即使我将 x 和 y 点传递给 MouseInputData,也不会发生单击。我想执行鼠标左键单击,而不需要实际移动光标。
波纹管是我拥有的类(它相当简单且直接)
namespace StackSolution.Classes
{
public static class SendInputClass
{
[DllImport("user32.dll", SetLastError = true)]
static extern uint SendInput(uint nInputs, ref INPUT pInputs, int cbSize);
[DllImport("user32.dll")]
static extern bool SetCursorPos(int X, int Y);
[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
static extern bool GetCursorPos(out Point lpPoint);
[StructLayout(LayoutKind.Sequential)]
struct INPUT
{
public SendInputEventType type;
public MouseKeybdhardwareInputUnion mkhi;
}
[StructLayout(LayoutKind.Explicit)]
struct MouseKeybdhardwareInputUnion
{
[FieldOffset(0)]
public MouseInputData mi;
[FieldOffset(0)]
public KEYBDINPUT ki;
[FieldOffset(0)]
public HARDWAREINPUT hi;
}
[StructLayout(LayoutKind.Sequential)]
struct KEYBDINPUT
{
public ushort wVk;
public ushort wScan;
public uint dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[StructLayout(LayoutKind.Sequential)]
struct HARDWAREINPUT
{
public int uMsg;
public short wParamL;
public short wParamH;
}
struct MouseInputData
{
public int dx;
public int dy;
public uint mouseData;
public MouseEventFlags dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[Flags]
enum MouseEventFlags : uint
{
MOUSEEVENTF_MOVE = 0x0001,
MOUSEEVENTF_LEFTDOWN = 0x0002,
MOUSEEVENTF_LEFTUP = 0x0004,
MOUSEEVENTF_RIGHTDOWN = 0x0008,
MOUSEEVENTF_RIGHTUP = 0x0010,
MOUSEEVENTF_MIDDLEDOWN = 0x0020,
MOUSEEVENTF_MIDDLEUP = 0x0040,
MOUSEEVENTF_XDOWN = 0x0080,
MOUSEEVENTF_XUP = 0x0100,
MOUSEEVENTF_WHEEL = 0x0800,
MOUSEEVENTF_VIRTUALDESK = 0x4000,
MOUSEEVENTF_ABSOLUTE = 0x8000
}
enum SendInputEventType : int
{
InputMouse,
InputKeyboard,
InputHardware
}
public static void ClickLeftMouseButton(int x, int y)
{
INPUT mouseInput = new INPUT();
mouseInput.type = SendInputEventType.InputMouse;
mouseInput.mkhi.mi.dx = x;
mouseInput.mkhi.mi.dy = y;
mouseInput.mkhi.mi.mouseData = 0;
//getting current cursor location
Point p;
if (GetCursorPos(out p))
SetCursorPos(x, y);
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTDOWN;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTUP;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
//returning cursor to previous position
SetCursorPos(p.X, p.Y);
}
}
}
如果我删除这样的获取光标位置,则相同的 ClickLeftMouseButton 函数将不会单击。
public static void ClickLeftMouseButton(int x, int y)
{
INPUT mouseInput = new INPUT();
mouseInput.type = SendInputEventType.InputMouse;
mouseInput.mkhi.mi.dx = x;
mouseInput.mkhi.mi.dy = y;
mouseInput.mkhi.mi.mouseData = 0;
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTDOWN;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTUP;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
}
先感谢您。
SendInput doesn't perform click mouse button unless I move cursor.
I would appreciate a help on this one, as I seems cannot wrap my head around it.
I have a program that perform mouse click on foreground window, in which I am using SendInput to emulate left mouse click.
The issue is, that if I move cursor to clicking position than SendInput will make the click, however if I don't move cursor than no click happens even trough I do pass x and y points to the MouseInputData. I would like to perform left mouse click without the need of actually moving the cursor at all.
Bellow is the class I have (it fairly simple and stright forward)
namespace StackSolution.Classes
{
public static class SendInputClass
{
[DllImport("user32.dll", SetLastError = true)]
static extern uint SendInput(uint nInputs, ref INPUT pInputs, int cbSize);
[DllImport("user32.dll")]
static extern bool SetCursorPos(int X, int Y);
[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
static extern bool GetCursorPos(out Point lpPoint);
[StructLayout(LayoutKind.Sequential)]
struct INPUT
{
public SendInputEventType type;
public MouseKeybdhardwareInputUnion mkhi;
}
[StructLayout(LayoutKind.Explicit)]
struct MouseKeybdhardwareInputUnion
{
[FieldOffset(0)]
public MouseInputData mi;
[FieldOffset(0)]
public KEYBDINPUT ki;
[FieldOffset(0)]
public HARDWAREINPUT hi;
}
[StructLayout(LayoutKind.Sequential)]
struct KEYBDINPUT
{
public ushort wVk;
public ushort wScan;
public uint dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[StructLayout(LayoutKind.Sequential)]
struct HARDWAREINPUT
{
public int uMsg;
public short wParamL;
public short wParamH;
}
struct MouseInputData
{
public int dx;
public int dy;
public uint mouseData;
public MouseEventFlags dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[Flags]
enum MouseEventFlags : uint
{
MOUSEEVENTF_MOVE = 0x0001,
MOUSEEVENTF_LEFTDOWN = 0x0002,
MOUSEEVENTF_LEFTUP = 0x0004,
MOUSEEVENTF_RIGHTDOWN = 0x0008,
MOUSEEVENTF_RIGHTUP = 0x0010,
MOUSEEVENTF_MIDDLEDOWN = 0x0020,
MOUSEEVENTF_MIDDLEUP = 0x0040,
MOUSEEVENTF_XDOWN = 0x0080,
MOUSEEVENTF_XUP = 0x0100,
MOUSEEVENTF_WHEEL = 0x0800,
MOUSEEVENTF_VIRTUALDESK = 0x4000,
MOUSEEVENTF_ABSOLUTE = 0x8000
}
enum SendInputEventType : int
{
InputMouse,
InputKeyboard,
InputHardware
}
public static void ClickLeftMouseButton(int x, int y)
{
INPUT mouseInput = new INPUT();
mouseInput.type = SendInputEventType.InputMouse;
mouseInput.mkhi.mi.dx = x;
mouseInput.mkhi.mi.dy = y;
mouseInput.mkhi.mi.mouseData = 0;
//getting current cursor location
Point p;
if (GetCursorPos(out p))
SetCursorPos(x, y);
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTDOWN;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTUP;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
//returning cursor to previous position
SetCursorPos(p.X, p.Y);
}
}
}
Same ClickLeftMouseButton function will not click if I remove getting cursor position like that.
public static void ClickLeftMouseButton(int x, int y)
{
INPUT mouseInput = new INPUT();
mouseInput.type = SendInputEventType.InputMouse;
mouseInput.mkhi.mi.dx = x;
mouseInput.mkhi.mi.dy = y;
mouseInput.mkhi.mi.mouseData = 0;
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTDOWN;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
mouseInput.mkhi.mi.dwFlags = MouseEventFlags.MOUSEEVENTF_LEFTUP;
SendInput(1, ref mouseInput, Marshal.SizeOf(new INPUT()));
}
Thank you in advance.
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使用
SendInput
函数时应考虑一些事项。如果未指定 MOUSEEVENTF_ABSOLUTE 标志,则 dx 和 dy(MouseInputData 结构)是相对于当前鼠标位置的相对坐标。如果您确实指定了
MOUSEEVENTF_ABSOLUTE
,则dx
和dy
是0到65535之间的绝对坐标。因此,如果您的x和y坐标是屏幕坐标,您应该使用以下函数计算 dx 和 dy:此外,在通过 SendInput 发送 MOUSEDOWN 和 MOUSEUP 事件之前,您必须将鼠标移动到要单击的控件on:
上面的代码假设
x
和y
是屏幕像素坐标。您可以使用以下代码计算 winform 上按钮(目标)的这些坐标:希望,这会有所帮助。
There are a few things you should consider when using the
SendInput
function.If you do not specify the
MOUSEEVENTF_ABSOLUTE
flag thendx
anddy
(MouseInputData structure) are relative coordinates to the current mouse position. If you do specifyMOUSEEVENTF_ABSOLUTE
thendx
anddy
are absolute coordinates between 0 and 65535. So if your x and y coordinates are screen coordinates you should use the following function to calculatedx
anddy
:Furthermore before you send the MOUSEDOWN and MOUSEUP events to via SendInput you have to move the mouse to the control you want to click on:
The above code assumes that
x
andy
are screen pixel coordinates. You can calculate those coordinates for a button (the target) on a winform by using the following code:Hope, this helps.