如何反转它的 Y 轴运动？

发布于 2024-12-13 23:18:19 字数 329 浏览 0 评论 0原文

我正在为 iPhone 制作一款涉及吹口哨的小游戏。手机会听到您口哨的频率，并相应地设置精灵在屏幕上的位置。代码如下：

if frequency > 1000 then
    soundbar.y = (frequency-1020)/10+30
end

这使得条形在 y 轴上在 30 和更高的位置之间移动，最高的啸叫寄存器位于 y 400 左右，这很好。只有一个问题。你吹得越高越高，酒吧就向下越远。有什么方法可以编辑我的公式，使栏从 208 开始，并且随着音调的增加，栏上升？

谢谢：）这让我困惑了一段时间！

原文

I'm making a little game for iPhone that involves whistling. The phone hears the frequency of your whistle, and sets the position of a sprite on the screen accordingly. Here is the code:

if frequency > 1000 then
    soundbar.y = (frequency-1020)/10+30
end

This makes the bar move between 30 and higher on the y axis, with the highest whistling register being at about y 400, which is fine.
There is only one problem. The higher you whistle, the further down the bar goes. Is there any way I can edit my formula, so that the bar starts at 208, and as the pitch increases, the bar rises?

Thanks :) This has had me stumped for a while!

分享到QQ

分享到微博