PHP-php call_user_func_array方法中的疑问

Question

废话不说，先看这段代码：

public function _check($checkData,$data) {
        $this->data = $data;
        foreach ($checkData as $checkKey=>$checkRule) {
//          赋值
            $this->value = $this->getCurrentValue($data[$checkKey]);
//          |中可以有&，但&不可有|，必须先判断顺
            // 取出错误提示消息
            $errorPrompt = array_pop($checkRule);
            if (is_object($checkRule[0])) {
                $call = array();
                $call[] = array_shift($checkRule);//对像
                $call[] = array_shift($checkRule);//方法
                array_unshift($checkRule, $this->value);//值
                if (!call_user_func_array($call, $checkRule)) return $this->checkInfo(false, $errorPrompt);
            }elseif (stripos($checkRule[0],'|' ) !== false) {//或者，必须 要在&之间判断
                if (!$this->checkOr($checkRule[0])) return $this->checkInfo(false, $errorPrompt);
            }elseif (stripos($checkRule[0], '&') !== false) {//与
                if (!$this->checkAnd($checkRule[0])) return $this->checkInfo(false, $errorPrompt);
            }else{
                $call_back_type = substr($checkRule[0], 0,1);
                if (in_array($call_back_type, $this->internalFunc)) {
                    if (!call_user_func_array(array($this,"_$call_back_type"), array(substr($checkRule[0], 1)))) return $this->checkInfo(false, $errorPrompt);
                }else {//普通函数
                    $call = substr(array_shift($checkRule), 1);//函数
                    array_unshift($checkRule, $this->value);//追加值
                    if (!call_user_func_array($call, $checkRule)) return $this->checkInfo(false, $errorPrompt);
                }
            }
        }

Answer 1

因为你写错了

 call_user_func_array(array($className,'before_storage')

看你的意思应该是

 call_user_func_array(array($newClass,'before_storage')