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如何从日期中获取星期几名称？

发布于 2024-12-13 12:07:40 字数 94 浏览 0 评论 0原文

给定 03/09/1982 我们怎么能说这是星期几呢？在本例中，时间为星期二。

是否可以在单个查询中获取？

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回忆那么伤 2024-12-20 12:07:40

SQL> SELECT TO_CHAR(date '1982-03-09', 'DAY') day FROM dual;

DAY
---------
TUESDAY

SQL> SELECT TO_CHAR(date '1982-03-09', 'DY') day FROM dual;

DAY
---
TUE

SQL> SELECT TO_CHAR(date '1982-03-09', 'Dy') day FROM dual;

DAY
---
Tue

（请注意，查询使用 ANSI 日期文字，它遵循 ISO-8601 日期标准并避免日期格式歧义。）

SQL> SELECT TO_CHAR(date '1982-03-09', 'DAY') day FROM dual;

DAY
---------
TUESDAY

SQL> SELECT TO_CHAR(date '1982-03-09', 'DY') day FROM dual;

DAY
---
TUE

SQL> SELECT TO_CHAR(date '1982-03-09', 'Dy') day FROM dual;

DAY
---
Tue

(Note that the queries use ANSI date literals, which follow the ISO-8601 date standard and avoid date format ambiguity.)

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如歌彻婉言 2024-12-20 12:07:40

晚了将近十年，但我认为有必要增强@Zohaib 的答案，因为它的结果取决于客户的语言。如果您向用户显示星期几名称，那绝对没问题，但如果您的代码依赖于它，我宁愿像这样控制语言：

SQL> SELECT TO_CHAR(date '1982-03-09', 'DAY', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---------
TUESDAY

SQL> SELECT TO_CHAR(date '1982-03-09', 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---
TUE

SQL> SELECT TO_CHAR(date '1982-03-09', 'Dy', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---
Tue

Nearly ten years late to the party, but I think it's neccessary to enhance @Zohaib 's answer as it's result depend on the language of the client. If you display the week day name to a user, it's absolutely fine, but if your code depends on it, I'd rather control the language like so:

SQL> SELECT TO_CHAR(date '1982-03-09', 'DAY', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---------
TUESDAY

SQL> SELECT TO_CHAR(date '1982-03-09', 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---
TUE

SQL> SELECT TO_CHAR(date '1982-03-09', 'Dy', 'NLS_DATE_LANGUAGE = ENGLISH') day FROM dual;

DAY
---
Tue

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入怼 2024-12-20 12:07:40

为了在 Oracle sql 中执行此操作，我尝试了这样的操作，它对我有用

SELECT 
    START_DATE,
    CASE WHEN START_DAY = 7 THEN 'SUNDAY'
         WHEN START_DAY = 1 THEN 'MONDAY'
         WHEN START_DAY = 2 THEN 'TUESDAY'
         WHEN START_DAY = 3 THEN 'WEDNESDAY'
         WHEN START_DAY = 4 THEN 'THURSDAY'
         WHEN START_DAY = 5 THEN 'FRIDAY'
         WHEN START_DAY = 6 THEN 'SATURDAY'
    END DAY_NAME
FROM 
(SELECT 
    TO_CHAR(T.START_DATE, 'DY') START_DAY,
    TO_CHAR(T.START_DATE, 'MM/DD/YYYY') START_DATE
       
FROM 
    TABLE T )

To do this in Oracle sql, I tried like this and it worked for me

SELECT 
    START_DATE,
    CASE WHEN START_DAY = 7 THEN 'SUNDAY'
         WHEN START_DAY = 1 THEN 'MONDAY'
         WHEN START_DAY = 2 THEN 'TUESDAY'
         WHEN START_DAY = 3 THEN 'WEDNESDAY'
         WHEN START_DAY = 4 THEN 'THURSDAY'
         WHEN START_DAY = 5 THEN 'FRIDAY'
         WHEN START_DAY = 6 THEN 'SATURDAY'
    END DAY_NAME
FROM 
(SELECT 
    TO_CHAR(T.START_DATE, 'DY') START_DAY,
    TO_CHAR(T.START_DATE, 'MM/DD/YYYY') START_DATE
       
FROM 
    TABLE T )

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