解析第二个节点的嵌套 yml 文件

Question

我有以下 yml 文件：

     Contours count: 8
     Contours:
             -
           Name: MI
           Count: 28
           Points:
               -
               x: 1116.
               y: 687.
               -
               x: 1.1224088134765625e+003
               y: 680.5911865234375000
               -

我有以下 C++ 代码，在 Qt 和 opencv 2.3.1 下：

cv::FileNode Points = fs["Contours"];
if (Points.type() != cv::FileNode::SEQ)
    ui->textEdit->append("is not a sequence! FAIL");
cv::FileNodeIterator it = Points.begin(), it_end = Points.end();
int idx = 0; int Count = 0;
std::vector<uchar> lbpval;
for( ; it != it_end; ++it, idx++ )
{
    Count += (int)(*it)["Count"];
    QString s = QString::number(Count);
    ui->textEdit->append(s);
}

我一直走到轮廓转到计数，迭代它们，并找到总和，但我卡在了点节点。我该如何解析这个节点？

Answer 1

for( ; it != it_end; ++it, idx++ )
{
    Count += (int)(*it)["Count"];
    QString s = QString::number(Count);
    ui->textEdit->append("Count: "+s);
    ui->textEdit->append("-");
    cv::FileNode Points = (*it)["Points"];
    cv::FileNodeIterator it = Points.begin(), it_end = Points.end();
    int idx = 0; int x = 0; int y = 0;
    for( ; it != it_end; ++it, idx++ )
    {
        x = (int)(*it)["x"];
        y = (int)(*it)["y"];
        points_xy.x = x; points_xy.y = y;
        QString s = QString::number(x);
        QString t = QString::number(y);
        ui->textEdit->append("x: "+s);
        ui->textEdit->append("y: "+t);
        ui->textEdit->append("-");
    }
}
fs.release();