PHP 一起使用 str_replace、substr 和 strpos

发布于 2024-12-12 07:37:09 字数 808 浏览 0 评论 0原文

我想做的是转换 youtube/vimeo 上视频的 url，返回一个可以嵌入到 iframe 中并自动执行视频嵌入代码的新 url。

这就像一个魅力。

$url  = "http://vimeo.com/29431603";
$orj_value = array("watch?v=", "http://vimeo.com/");
$new_value   = array("embed/", "http://player.vimeo.com/video/");
$url = str_replace($orj_value, $new_value, $url);
echo $url;

你知道，youtube 也会在以 & 开头的 url 中广告一个丑陋的字符串，所以当我

$url = substr($url, 0, strpos($url, "&"));

在它之前

echo $url;

添加它时，它会删除 youtube url 中不需要的部分。但是，vimeo 代码中没有 &里面只是不返回任何东西。似乎添加新行后，代码想要看到一个 &网址内；否则 echo $url var 显示空白屏幕。

2-对于dailymotion，我需要删除第一个_之后的所有内容我应该如何编辑下面的行才能包含 dailymotion 的支持？

$url = substr($url, 0, strpos($url, "&"));

预先感谢任何愿意回答的人:)

原文

What I am trying to do is to convert url of a video on youtube/vimeo return a new url that can be embed into an iframe and automate video embed codes.

This is working like a charm.

$url  = "http://vimeo.com/29431603";
$orj_value = array("watch?v=", "http://vimeo.com/");
$new_value   = array("embed/", "http://player.vimeo.com/video/");
$url = str_replace($orj_value, $new_value, $url);
echo $url;

You know, youtube ads an ugly string too into url that starts with &, so when i include

$url = substr($url, 0, strpos($url, "&"));

before

echo $url;

it strips out the unwanted part of youtube url. But then, vimeo code which has no & inside just does not return anything. Seems after adding new line, code wants to see a & inside the url; otherwise to echo $url var displays blank screen.

2- For dailymotion, i need to strip out everything after first _
How should i edit the line below in order to include support of dailymotion too?

$url = substr($url, 0, strpos($url, "&"));

Thanks in advance to anyone going to answer :)

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執念 2024-12-19 07:37:09

如果 strpos() 找不到您搜索的字符，它将返回 false，这可能会混淆 substr()。

尝试这样的事情：

$url = strpos($url, "&") ? substr($url, 0, strpos($url, "&")) : $url;

至于你的评论：

if(strpos($url, "&")) {
    $url = substr($url, 0, strpos($url, "&"));
} else if(strpos($url, "_")) {
    $url = substr($url, 0, strpos($url, "_"));
}

有更优雅的方法可以做到这一点（例如 REGEX），但这可以。请注意 &或者 _ 不能是字符串中的第一个字符，如果您想允许将 !== false 添加到条件中。

If strpos() can't find the character you search for it will return false, which could confuse substr().

Try something like this:

$url = strpos($url, "&") ? substr($url, 0, strpos($url, "&")) : $url;

As for your comment:

if(strpos($url, "&")) {
    $url = substr($url, 0, strpos($url, "&"));
} else if(strpos($url, "_")) {
    $url = substr($url, 0, strpos($url, "_"));
}

There are more elegant ways to do it (ex. REGEX) but this will do. Note that & or _ can't be the first character in string if you want to allow this add !== false to the condition.

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