如何在 Android Widget 类中构建 onReceive 方法来切换 ImageView 的图像？
感谢一些教程，我现在已经构建了我的第一个可用的小 Android Widget。
它有一个 ImageView，当我点击它一次时，它会改变它的图像。
但现在我想多次单击它以更改为另一个图像，就像切换按钮一样。
因此，我在 onReceive 方法中设置了以下 IF 约束：
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(ACTION_WIDGET_RECEIVER)) {
try {
if(counter %2 == 0) {
views.setImageViewResource(R.id.iv1, R.drawable.button_state1);
cn1 = new (context, MyDailyPlateWidgetProvider.class);
AppWidgetManager.getInstance(context).updateAppWidget(cn1, views);
counter++;
} else { counter++;
views.setImageViewResource(R.id.iv1, R.drawable.button_state2);
cn2 = new (context, MyDailyPlateWidgetProvider.class);
AppWidgetManager..getInstance(context).updateAppWidget(cn2, views);
}
}
// ...
}
但在我看来，我无法使用 counter++ 持续修改我的 int counter 。
有没有办法通过单击我的小部件或其他解决方案来设置我的类的 int ，以在小部件中构建某种切换行为？
在没有运行后台服务的情况下这是否可能？
Thanks to some tutorials I have now built my first working little Android Widget.
It has an ImageView which changes it's image when I click on it once.
But now I want to click on it multiple times to change to another image just like a toggle button.
Therefore I've set the following IF constraint in my onReceive method:
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(ACTION_WIDGET_RECEIVER)) {
try {
if(counter %2 == 0) {
views.setImageViewResource(R.id.iv1, R.drawable.button_state1);
cn1 = new (context, MyDailyPlateWidgetProvider.class);
AppWidgetManager.getInstance(context).updateAppWidget(cn1, views);
counter++;
} else { counter++;
views.setImageViewResource(R.id.iv1, R.drawable.button_state2);
cn2 = new (context, MyDailyPlateWidgetProvider.class);
AppWidgetManager..getInstance(context).updateAppWidget(cn2, views);
}
}
// ...
}
But it seems to me that I can't modify my int counter with counter++ persistently.
Is there any way to set the int of my class through a click on my widget or an other solution to build some kind of toggle behavior in a widget?
Is this even possible without a running background service?
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否则，您无法增加计数器。假设计数器首先为 0，那么 (counter %2 == 0) 为 true，因此它执行第一部分，并递增计数器。下一次 counter 是 1，所以 (counter %2 == 0) 是 false，所以它执行第二部分...从那时起每次，因为 counter 永远是 1！每次只需增加计数器即可。
In the Else, you fail to increment the counter. Imagine counter is first 0, so then (counter %2 == 0) is true, so it does the first part, and increments the counter. Next time counter is 1, so (counter %2 == 0) is false, so it does the second part... every time from then on, because counter is forever 1! Just increment counter every time.