方案按长度排序向量

Question

我有一个 dfs 方法将返回向量列表，如何根据向量的长度对元素进行排序。

(define (dfs path) ;path store vector index, start from 0 
 (cond
 ((dfsStack' empty?)(newline))
  (else (set! currentPath (dfsStack' pop!))
      (findLast (car currentPath) 0)
      (checkUnvisited (cdr (vector-ref network lastNum)))

      (cond
        ((eq? lastName reach) ;reach point
         (duplicate path)          
         (dfs (+ path 1)) ;continue dfs to find next path         
         )
        ((and (not (eq? lastName reach))(eq? unvisited #t)) ;no more neighbours
         (dfs path)
         ) 
        ((and (not (eq? lastName reach))(eq? unvisited #f)) ;found the neighbours
         (pushStack lastNeighbours currentPath)
         (dfs path)
         )
        );//end cond
      )   
);//end cond
);//end dfs

Answer 1

与上一个问题 使用合并排序的方案向量 的方式相同

，只需替换 length 与向量长度。