用于包装模型和/或转换模型 (POJO) 的良好 JAXB 设计模式？

发布于 2024-12-12 02:19:18 字数 1156 浏览 0 评论 0原文

我有以下模型，

class MyClass {
    id
    someRandomString
}

我想将此 POJO 返回给客户端...

<Root>
    <random>if + randomstring</random>
</Root>

基本上我正在处理一个非常面向消息的服务，所以我需要将模型包装并转换为出站 XML 格式...同样继续输入端

我有这个XML...

<Root>
    <Username>
    <Password>
    <Action> <-- Some action or service to perform
    <SomeModel1>
    <SomeModel2>
</Root>

所以root、用户名和密码是常量元素，而SomeModel可以根据“服务”进行更改

基本上我正在寻找一种XML与模型不匹配的设计模式需要有一个转变……

或者如果我做了...

class MyClass {
    id
    someRandomString
    random

    @XMLTransient
    getId()


    @XMLTransient
    getSomeRandomString()


    getRandom() {
        return id + someRandomString
    }
}

所以JAXB只会映射getRandom...

我的另一个想法是创建一堆代表最终输出的类，并将值设置为这些...

所以

class MyResponse {
    randomString
    status
    someOtherFieldRequired in response
}

然后我可以做...

myResponse.setRandomString(myClass.getId() + myClass.getSomeRandomString());

原文

I have the following model

class MyClass {
    id
    someRandomString
}

I would like to return this POJO to the client as...

<Root>
    <random>if + randomstring</random>
</Root>

Basically I'm dealing with a very message oriented service so I need to wrap and transform the model to the outbound XML format... Same goes on the input side

I have this XML...

<Root>
    <Username>
    <Password>
    <Action> <-- Some action or service to perform
    <SomeModel1>
    <SomeModel2>
</Root>

So the root and username and password are constant elements while the SomeModel can change based on the "service"

Bassically i'm looking for a design-pattern where the XML doesn't match the model and there needs to be a transformation to and from...

Or what if I did...

class MyClass {
    id
    someRandomString
    random

    @XMLTransient
    getId()


    @XMLTransient
    getSomeRandomString()


    getRandom() {
        return id + someRandomString
    }
}

So JAXB will only map getRandom...

Another idea I have is create a bunch of classes that will represent the final output and just set the values to thoses...

class MyResponse {
    randomString
    status
    someOtherFieldRequired in response
}

and then I can do...

myResponse.setRandomString(myClass.getId() + myClass.getSomeRandomString());

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星星的軌跡 2024-12-19 02:19:18

您可以使用 XmlAdapter 与 XmlJavaTypeAdapter，但我认为它可能需要您将 id 和 someRandomString 属性封装到一个单独的类中。如果可能的话，我不知道如何直接将元素值分散到两个单独的 bean 属性上。

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北座城市 2024-12-19 02:19:18

您可以使用 id 和 someRandomString 字段来分隔元素，并使用样式表将元素合并为一个。 JAXB 提供了与 javax.xml.transform API 相匹配的 JAXBSource 类：

MyClass myClass = new MyClass();
myClass.setId(123);
myClass.setSomeRandomString("FOO");

TransformerFactory tf = TransformerFactory.newInstance();
StreamSource xslt = new StreamSource(new FileInputStream("my-xslt.xml"));
Transformer t = tf.newTransformer(xslt);

JAXBContext jc = JAXBContext.newInstance(MyClass.class);
JAXBSource source = new JAXBSource(jc, myClass);

StreamResult result = new StreamResult(System.out);

t.transform(source, result);

You could the id and someRandomString fields to separate elements and use a style sheet to combine the elements into one. JAXB offers the JAXBSource class that fits it with the javax.xml.transform APIs:

MyClass myClass = new MyClass();
myClass.setId(123);
myClass.setSomeRandomString("FOO");

TransformerFactory tf = TransformerFactory.newInstance();
StreamSource xslt = new StreamSource(new FileInputStream("my-xslt.xml"));
Transformer t = tf.newTransformer(xslt);

JAXBContext jc = JAXBContext.newInstance(MyClass.class);
JAXBSource source = new JAXBSource(jc, myClass);

StreamResult result = new StreamResult(System.out);

t.transform(source, result);

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