将 html 与 php 搜索结果混合在一起?
我试图使不同的行有换行符,但它不起作用。
这是怎么做到的!?请检查下面我的代码
谢谢大家!
詹姆斯
<?php
$conn = mysql_connect("", "", "");
if (!$conn) {
echo "Unable to connect to DB: " . mysql_error();
exit;
}
{
$search = "%" . $_POST["search"] . "%";
$searchterm = "%" . $_POST["searchterm"] . "%";
}
if (!mysql_select_db("")) {
echo "Unable to select mydbname: " . mysql_error();
exit;
}
$sql = "SELECT name,lastname,email
FROM test_mysql
WHERE name LIKE '$search%' AND lastname LIKE '$searchterm'";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
while ($row = mysql_fetch_assoc($result)) {
echo $row["name"];
echo $row["lastname"];
echo $row["email"];
}
mysql_free_result($result);
?>
<?php echo $row["name"];?>
<br>
<?php echo $row["lastname"];?>
<br>
<?php echo $row["email"];?>
I am trying to make the different the different rows have line breaks but its not working.
How is this done!? Please check my code below
Thanks guys!
James
<?php
$conn = mysql_connect("", "", "");
if (!$conn) {
echo "Unable to connect to DB: " . mysql_error();
exit;
}
{
$search = "%" . $_POST["search"] . "%";
$searchterm = "%" . $_POST["searchterm"] . "%";
}
if (!mysql_select_db("")) {
echo "Unable to select mydbname: " . mysql_error();
exit;
}
$sql = "SELECT name,lastname,email
FROM test_mysql
WHERE name LIKE '$search%' AND lastname LIKE '$searchterm'";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
while ($row = mysql_fetch_assoc($result)) {
echo $row["name"];
echo $row["lastname"];
echo $row["email"];
}
mysql_free_result($result);
?>
<?php echo $row["name"];?>
<br>
<?php echo $row["lastname"];?>
<br>
<?php echo $row["email"];?>
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打败我你觉得很难:
Beats me what you find so hard about it: