带有 PartialViews 的无效 ModelState

发布于 2024-12-11 23:11:30 字数 886 浏览 0 评论 0原文

我有以下操作，

[GET("Foo")]
public virtual ActionResult Foo()
{
    return View(new FooViewModel());
}

此操作的视图

@{ Html.RenderAction(MVC.FooBar.AddFoo()); }

使用控制器操作

[ChildActionOnly]
[GET("Foo/Add")]
public virtual ActionResult AddFoo()
{
    var viewModel = new AddFooViewModel();

    return PartialView(viewModel);
}

[POST("Foo/Add")]
public virtual ActionResult AddFooPost(AddFooViewModel viewModel)
{
    // If ModelState is invalid, how do I redirect back to /Foo 
    // with the AddFooViewModel ModelState intact??
    if (!ModelState.IsValid)
        return MVC.FooBar.Foo();

    // ... persist changes and redirect
    return RedirectToAction(MVC.FooBar.Foo());
}

调用此部分视图如果有人提交带有 ModelState 错误的 AddFoo 表单，我希望 POST 操作重定向回 /Foo 并显示带有 ModelState 错误的 AddFoo 部分视图。处理这个问题的最佳方法是什么？

原文

I have the following action

[GET("Foo")]
public virtual ActionResult Foo()
{
    return View(new FooViewModel());
}

the view for this action calls this partial view

@{ Html.RenderAction(MVC.FooBar.AddFoo()); }

with controller actions

[ChildActionOnly]
[GET("Foo/Add")]
public virtual ActionResult AddFoo()
{
    var viewModel = new AddFooViewModel();

    return PartialView(viewModel);
}

[POST("Foo/Add")]
public virtual ActionResult AddFooPost(AddFooViewModel viewModel)
{
    // If ModelState is invalid, how do I redirect back to /Foo 
    // with the AddFooViewModel ModelState intact??
    if (!ModelState.IsValid)
        return MVC.FooBar.Foo();

    // ... persist changes and redirect
    return RedirectToAction(MVC.FooBar.Foo());
}

If somebody submits the AddFoo form with ModelState errors, I want the POST action to redirect back to /Foo and show the AddFoo partial view with the ModelState errors. What's the best approach to handle this?

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计㈡愣 2024-12-18 23:11:30

我认为您可以通过两种方式实现这一目标：

使用会话状态使用
查询字符串参数传递数据

我更喜欢第二个选项。

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狂之美人 2024-12-18 23:11:30

我最终将视图模型放入 TempData 中，如下所示，并使用控制器上的 ModelStateToTempData 属性

[ChildActionOnly]
[GET("Foo/Add")]
public virtual ActionResult AddFoo()
{
    var viewModel = TempData["AddFooViewModel"] as AddFooViewModel ?? new AddFooViewModel();

    return PartialView(viewModel);
}

[POST("Foo/Add")]
public virtual ActionResult AddFooPost(AddFooViewModel viewModel)
{
    // If ModelState is invalid, how do I redirect back to /Foo 
    // with the AddFooViewModel ModelState intact??
    if (!ModelState.IsValid)
    {
        TempData["AddFooViewModel"] = viewModel;
        return RedirectToAction(MVC.FooBar.Foo());
    }

    // ... persist changes and redirect
    return RedirectToAction(MVC.FooBar.Foo());
}

I ended up putting the viewmodel into TempData like this with the ModelStateToTempData attribute on the controller

[ChildActionOnly]
[GET("Foo/Add")]
public virtual ActionResult AddFoo()
{
    var viewModel = TempData["AddFooViewModel"] as AddFooViewModel ?? new AddFooViewModel();

    return PartialView(viewModel);
}

[POST("Foo/Add")]
public virtual ActionResult AddFooPost(AddFooViewModel viewModel)
{
    // If ModelState is invalid, how do I redirect back to /Foo 
    // with the AddFooViewModel ModelState intact??
    if (!ModelState.IsValid)
    {
        TempData["AddFooViewModel"] = viewModel;
        return RedirectToAction(MVC.FooBar.Foo());
    }

    // ... persist changes and redirect
    return RedirectToAction(MVC.FooBar.Foo());
}

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