Zend Framework：是否有视图助手在布局类中显示视图名称？
正如标题所示，我试图找到一种显示当前作为布局一部分显示的视图标题的方法。我正在尝试执行此操作，以便在选择不同视图时动态填充页面标题。
在伪代码中：
<div>
<div id="header"><h1>My website</h1></div>
<div id="main">
<?php echo "<h2>" . SOME WAY OF ECHOING THE VIEW NAME HERE . "</h2>"; ?>
<?php echo $this->layout()->content; ?>
</div>
<div id="footer"><p>2011 My website.com></p>
</div>
我已经浏览了 Zend 文档，我能找到的最接近的东西是标题链接。但是，我无法从此帮助程序获取值并将其插入变量中，以便我可以将其文本显示为视图的页面标题。
谢谢。
As the title suggests, I'm trying to find a way of displaying the title of the View currently being displayed as part of the layout. I'm trying to do this so that the page title is dynamicly populated when a different view is selected.
In psuedocode:
<div>
<div id="header"><h1>My website</h1></div>
<div id="main">
<?php echo "<h2>" . SOME WAY OF ECHOING THE VIEW NAME HERE . "</h2>"; ?>
<?php echo $this->layout()->content; ?>
</div>
<div id="footer"><p>2011 My website.com></p>
</div>
I've been through the Zend documentation and the closest thing I could find was the headlink. However, I was unable to get the value from this helper and shoehorn it into a variable so that I could display its text as a page header for the view.
Thanks.
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您可以将操作名称（或根据需要与模块组合）传递到控制器内的布局。
$layout = $this->_helper->layout->getLayoutInstance();
$layout->viewName = $this->_getParam("action");
有点脏，但可以用
You could pass the action name (or combine with the module if needed) to the layout within the controller.
$layout = $this->_helper->layout->getLayoutInstance();
$layout->viewName = $this->_getParam("action");
Kind of dirty, but it would work
我不太确定我是否理解正确，但是有一个叫做 ZendFramework 中的占位符。基本上，您定义占位符，然后用您想要的任何内容填充它。
I´m not quite sure if I understood you right, but there´s something called a placeholder in ZendFramework. Basically you define the placeholder and fill it afterwards with whatever you want.