名称数组 = 获取正确的文件

发布于 2024-12-11 20:09:35 字数 831 浏览 0 评论 0原文

我正在尝试编写一个文件列表并将它们放入一个数组中。必须更改调用外部内容的页面上的内容。

我找到了这段小代码并试图使其工作。 LINK（最后评论）

$all_pages=array("main","page_two","page_three");    
$page = $_GET['page'];    
if( isset($page) and array_key_exists("$page", $all_pages) ) // added a missing ')'
{
include('subfolder/folder/'.$_GET['$page'].'.html');
}

好吧，这是行不通的。只是无法找到正确的文件。（内容始终显示为空）。

我（尝试）将这些文件称为：

<ul>    
   <li><a href="template.php?main">Main content</a></li>
   <li><a href="template.php?page_two">Second content</a></li>
   <li><a href="template.php?page_three">Third content</a></li>
</ul>

提前致谢！

原文

I'm trying to write a list of files and drop them into an array.
Have to change the content on a page calling external contents.

I've found this little piece of code and trying to make it work.
LINK (last comment)

$all_pages=array("main","page_two","page_three");    
$page = $_GET['page'];    
if( isset($page) and array_key_exists("$page", $all_pages) ) // added a missing ')'
{
include('subfolder/folder/'.$_GET['$page'].'.html');
}

well, this does not work.
Just can't get to the right file. (the content shows always empty).

I (try to) call the files like:

<ul>    
   <li><a href="template.php?main">Main content</a></li>
   <li><a href="template.php?page_two">Second content</a></li>
   <li><a href="template.php?page_three">Third content</a></li>
</ul>

Thanks in advance!

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等往事风中吹 2024-12-18 20:09:35

您必须使用 in_array() 来测试允许的值。 array_key_exists 要求页面名称是数组键。

其次， $_GET["page"] 将为空，因为您没有该名称的 get 参数。您必须调整您的链接：（

   <li><a href="template.php?page=main">Main content</a></li>
   <li><a href="template.php?page=page_two">Second content</a></li>
   <li><a href="template.php?page=page_three">Third content</a></li>

或者使用$_SERVER["QUERY_STRING"]。但是您可能不想这样做。）

您的第三个问题是使用：

include('subfolder/folder/'.$_GET['$page'].'.html');
                            ^^^    ^^^

您应该在此处仅使用 $page 变量，该变量已从 $_GET 中读取。再次使用该名称作为密钥将不起作用。而且您还在单引号中使用了它（双重错误，但幸运的是没有效果）。

所以正确的是：

$all_pages = array("main", "page_two", "page_three");    
$page = $_GET['page'];
if ( in_array($page, $all_pages) )
{
    include('subfolder/folder/'.$page.'.html');
}

You would have to use in_array() to test for allowed values. array_key_exists would require the page names to be array keys.

Secondly, $_GET["page"] will be empty, as you didn't have a get parameter of that name. You must adapt your links:

   <li><a href="template.php?page=main">Main content</a></li>
   <li><a href="template.php?page=page_two">Second content</a></li>
   <li><a href="template.php?page=page_three">Third content</a></li>

(Or otherwise use $_SERVER["QUERY_STRING"]. But you probably don't want to do that.)

Your third problem was using:

include('subfolder/folder/'.$_GET['$page'].'.html');
                            ^^^    ^^^

You should have used just the $page variable here, which you already read from $_GET. Using that name as key again would not work. And you additionally used it ín single quotes (doubly wrong, but luckily without effect).

So correct would be:

$all_pages = array("main", "page_two", "page_three");    
$page = $_GET['page'];
if ( in_array($page, $all_pages) )
{
    include('subfolder/folder/'.$page.'.html');
}

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